If you are looking for the value of X i believe it is 21.6
Subtract .10 from both sides to get
.25X=5.40
Then divide both sides by .25
Answer:
Option C
Step-by-step explanation:
complete question
A. 35[3]6cB. 12[3]12cC. 12[3]6cD.72c
The given equation can be written as
5^3√6c+7^3√6c
5 *
+ 7 * ![\sqrt{3 *3*2c}](https://tex.z-dn.net/?f=%5Csqrt%7B3%20%2A3%2A2c%7D)
5 * 3 *
+ 7 * 3 *![\sqrt{2c}](https://tex.z-dn.net/?f=%5Csqrt%7B2c%7D)
15 *
+ 21 *![\sqrt{2c}](https://tex.z-dn.net/?f=%5Csqrt%7B2c%7D)
36 *![\sqrt{2c}](https://tex.z-dn.net/?f=%5Csqrt%7B2c%7D)
12 [3]*![\sqrt{2c}](https://tex.z-dn.net/?f=%5Csqrt%7B2c%7D)
Option C is correct
Answer:4months
Step-by-step explanation:
Answer:
Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis
Step-by-step explanation:
plz forgive me if my answer is wrong
Answer:
see the attachments for the two solutions
Step-by-step explanation:
When the given angle is opposite the shorter of the given sides, there will generally be two solutions. The exception is the case where the triangle is a right triangle (the ratio of the given sides is equal to the sine of the given angle). If the given angle is opposite the longer of the given sides, there is only one solution.
When a side and its opposite angle are given, as here, the law of sines can be used to solve the triangle(s). When the given angle is included between two given sides, the law of cosines can be used to solve the (one) triangle.
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Here, the law of sines can be used to solve the triangle:
A = arcsin(a/c·sin(C)) = arcsin(25/24·sin(70°)) = 78.19° or 101.81°
B = 180° -70° -A = 31.81° or 8.19°
b = 24·sin(B)/sin(70°) = 13.46 or 3.64