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nordsb [41]
3 years ago
7

Which of the two numbers is a better estimate for the square root of 12? Explain.

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

3 < square root of 12 < 4

Step-by-step explanation:

When estimating square roots find the closest perfect square.

So the previous root of 12 is √9 because it is 3, and the next root is √16 which is 4.

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12 gallons of water fill a tank of 3/4 capacity if the tank is fill full how many half gallons bottles can be filled with water
Advocard [28]
If 12= 3/4, then 16=4/4 would be a full tank.

The question is asking how many half gallon bottles can be filled, if there’s 16 full gallons, you’d multiply 16 by 2, and get 32.

Your answer is 32 half gallons
6 0
4 years ago
The result I got was e^{2} which i'm not sure is the right answer
san4es73 [151]

Answer:

e²

Step-by-step explanation:

hello : here is the solution

7 0
3 years ago
What is the y=mx+b of this?
pochemuha
I think it’s y=-1x+ -8 or could be written as y=-1x-8
3 0
3 years ago
Solve for t.<br><br> −3t≥39<br><br><br><br><br> t≥−13<br><br><br> t≤13<br><br> t≥13<br><br> t≤−13
kozerog [31]

One solution was found :  t ≤ -13 (Last answer choice)

Pull out like factors :

-3t - 39  =   -3 • (t + 13)

Divide both sides by  -3  

Remember to flip the inequality sign:  

Solve Basic Inequality :

Subtract  13  from both sides to get t≤−13


5 0
3 years ago
Two trains are 400 miles apart, and their speeds differ by 10 mph. They travel toward each other and meet in 4 hours. Find the s
Katen [24]
So.. the two trains, are 400 miles apart, their speeds differ by 10, so one train is faster than the other.. .let's say   train A is faster than train B, by 10mph

so if train A has a speed rate of "r", then B has a rate of "r - 10"

after train A has beeng running for 4hrs, it has travelled a distance "d"

train B has travelled also for 4hrs, they're both 400 miles apart, and travelling towards each other, so the total distance travelled by both is 400miles

so after 4hours B has travelled the slack from 400 and "d", namely 400 - d

recall your d = rt --> distance = rate * time

\bf \begin{array}{lccclll}&#10;&distance&rate&time\\&#10;&-----&-----&-----\\&#10;\textit{Train A}&d&r&4\\&#10;\textit{Train B}&400-d&r-10&4&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;&#10;\begin{cases}&#10;\boxed{d}=4r\\&#10;400-d=(r-10)4\\&#10;----------\\&#10;400-\boxed{4r}=(r-10)4&#10;\end{cases}

solve for "r", to find the speed of the faster train A

what's the speed of B? well, B's rate is r - 10
4 0
3 years ago
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