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sveta [45]
3 years ago
11

A spring with a mass on the end of it hangs in equilibrium a distance of 0.4200 m above the floor. The mass is pulled down a dis

tance 0.0600 m below the original position, released, and allowed to oscillate. How high above the floor is the mass at the highest point in its oscillation
Physics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

0.48 m

Explanation:

I'm assuming that this takes place in an ideal situation, where we neglect a host of factors such as friction, weight of the spring and others

If the mass is hanging from equilibrium at 0.42 m above the floor, from the question, and it is then pulled 0.06 m below that particular position. This pulling is a means of adding more energy into the spring, when it is released, the weight compresses the spring and equals its distance (i.e, 0.06 m) above the height.

0.42 m + 0.06 m = 0.48 m

At the highest point thus, the height is 0.48 m above the ground.

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A fisherman notices that his boat is moving up and down periodically, owing to waves on the surface of the water. It takes 2.5 s
gulaghasi [49]

(a) 0.96 m/s

The period of the wave corresponds to the time taken for one complete oscillation of the boat, from the highest point to the highest point again. Since the time between the highest point and the lowest point is 2.5 s, the period is twice this time:

T=2\cdot 2.5 s=5.0 s

The frequency of the waves is the reciprocal of the period:

f=\frac{1}{T}=\frac{1}{5.0 s}=0.20 Hz

The wavelength instead is just the distance between two consecutive crests, so

\lambda=4.8 m

And the wave speed is given by:

v=\lambda f=(4.8 m)(0.20 Hz)=0.96 m/s

(b) 0.265 m

The total distance between the highest point of the wave and its lowest point is

d = 0.53 m

The amplitude is just the maximum displacement of the wave from the equilibrium position, so it is equal to half of this distance. So, the amplitude is

A=\frac{d}{2}=\frac{0.53 m}{2}=0.265 m

(c) Amplitude: 0.15 m, wave speed: same as before

In this case, the amplitude of the wave would be lower. In fact,

d = 0.30 m

So the amplitude would be

A=\frac{d}{2}=\frac{0.30 m}{2}=0.15 m

Instead, the wave speed would not change, since neither the frequency nor the wavelength of the wave have changed.

8 0
3 years ago
Does the planet exert a torque on the meteoroid with respect to the center of mass of the planet? Why or why not?
ra1l [238]

Answer:

yes

Explanation:

because the planet exerts a centripetal force on the meteorold

4 0
3 years ago
Help please!!!!!!!!!!!!!!!!!!!!
Pavel [41]
Looks like you need to review through the lesson and take notes as it tells you in the lesson what each of these are.
8 0
3 years ago
How did France and Spain use what they learned during the American revolution to benefit their own countries
alexgriva [62]
Spain declared war on Britain as an ally of France, itself an ally of the American colonies, and provided supplies and munitions to the American forces. Beginning in 1776, it jointly funded Roderigue Hortalez and Company, a trading company that provided critical military supplies.
4 0
3 years ago
Why is 30% recommended as the minimum Michelson contrast?
forsale [732]

Answer:

Explained

Explanation:

Michelson contrast is used for patterns where the distribution of bright and dark segments is nearly equal.

It is given by:

m= \frac{I_{max}-I{min}}{I_{max}+I{min} }

where I_max = maximum illumination and I_min = minimum illumination

we know that

typically, I_min = 54% of I_max  (general standard)

or I_min = 0.54 I_max

putting this value in above equation to get m

this approximately corresponds to m = 0.3 or 30%

hence, 30% recommended as the minimum Michelson contrast

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3 years ago
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