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sveta [45]
3 years ago
11

A spring with a mass on the end of it hangs in equilibrium a distance of 0.4200 m above the floor. The mass is pulled down a dis

tance 0.0600 m below the original position, released, and allowed to oscillate. How high above the floor is the mass at the highest point in its oscillation
Physics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

0.48 m

Explanation:

I'm assuming that this takes place in an ideal situation, where we neglect a host of factors such as friction, weight of the spring and others

If the mass is hanging from equilibrium at 0.42 m above the floor, from the question, and it is then pulled 0.06 m below that particular position. This pulling is a means of adding more energy into the spring, when it is released, the weight compresses the spring and equals its distance (i.e, 0.06 m) above the height.

0.42 m + 0.06 m = 0.48 m

At the highest point thus, the height is 0.48 m above the ground.

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Which of the following is one of the three main fuels that a star uses for fusion
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Hydrogen, helium, and carbon.
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A stone is thrown upward from the top of a building at an angle of 30° to the horizontal and with an initial speed of 20 m/s. Th
Hitman42 [59]

Answer:

Explanation:

Given

inclination \theta =30^{\circ}

initial speed u=20\ m/s

Point of release is 45 m above the ground

Considering stone to be a projectile, so time taken by projectile for its zero vertical displacement is

t_1=\frac{2u\sin \theta }{g}

t_1=\frac{2\times 20\times \sin 30}{10}

t_1=2\ s

Now after completing zero vertical displacement , stone needs to travel another 45 m in downward direction with initial speed u=20\sin 30

h=u_yt+\frac{1}{2}a_yt^2

where, h=height

u_y=vertical velocity

a_y=vertical acceleration

t_0=time

45=20\sin 30+\frac{1}{2}(9.8)(t_0)^2

t_0^2=\frac{70}{9.8}

t_0=2.64\ s

thus total time time required is t=t_0+t_1=2.64+2=4.64\ s

vertical velocity just before hitting

v_y=\sqrt{u_y^2+2\times a_y\times s}

v_y=\sqrt{10^2+2\times 10\times 45}

v_y=\sqrt{1000}=31.622\ m/s

Horizontal velocity v_x=u\cos 30=17.32\ m/s

Net velocity Just before hitting =\sqrt{v_x^2+v_y^2}

=\sqrt{(17.32)^2+(31.62)^2}

=\sqrt{1299.82}=36.05\ m/s

                 

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3 years ago
The tendency of an object to resist a change in its motion is called
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Answer:

inertia

Explanation:

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How is electron movement related to the bonding in sodium chloride? A) The atomic orbitals overlap and share electrons causing a
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Answer: Option (C) is the correct answer.

Explanation:

Sodium has atomic number 11 and its electronic distribution is 2, 8, 1. Whereas chlorine has atomic number 17 and its electronic configuration is 2, 8, 7.

Therefore, we can see that sodium has one extra electron and chlorine has deficiency of one electron.

So, in order to complete their octet sodium will give its one valence electron to the chlorine atom. Hence, there is exchange of electrons and thus it will result in the formation of ionic bond.

Thus, we can conclude that in sodium chloride electron movement is related to the bonding as electrons exchange creating ions to form an ionic bond by electrostatic attraction.

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