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3 years ago

How does the sun's energy most directly influence precipitation in an area?

1 answer:

5 0

The sun's energy influences climate in various ways. For example the latitudes at the equator receive more energy from the sun and therefore have warmer temperatures, On the other hand the sun's energy influences precipitation in a climate by driving the water cycle which determines precipitation.The sun is what makes the water cycle take place. That is the sun provides energy or heat to the earth; the heat causes liquid and frozen water to evaporate into water vapor gas, which rises high in the sky to form clouds ( precipitation), that in turn give us rain

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What are the five plants you can see from earth without a telescope?

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The five planets that you can see from Earth without a telescope are Mercury, Venus, Mars, Jupiter and Saturn.

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3 years ago

A dog is trained to sit and shake hands these traits are most likely

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Taught not inherited

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Axit amin có chức năng gì sau đây

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3 years ago

Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 23.0 and carries a cl

Bond [772]

Answer:

I = 33.04A

Explanation:

The magnetic field at the center of a loop of wire is proportional to the current flowing through the wire and inversely proportional to the radius

So therefore we have:

20/23 = I/38.0

We then solve for I

cross multiplying we have 20 x 38 = 23 x I

I = 20 x 38/ 23

I = 33.04A

7 0

3 years ago

A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is applied. A 0.500-kg particle res

garri49 [273]

Answer:

ω = 22.36 Hz

f = 3.56 Hz

T = 0.28 s.

Explanation:

a) The angular frequency (ω), can be calculated using the following equation:

$\omega = \sqrt{\frac{k}{m}} = \sqrt{\frac{F}{x*m}}$

Where:

k: is the spring constant = F/x

m: is the mass of the particle = 0.500 kg

F: is the force applied = 7.50 N

x: is the displacement = 3.00 cm = 0.03 m

$\omega = \sqrt{\frac{7.50 N}{0.03 m*0.500 kg}} = 22.36 s^{-1} = 22.36 Hz$

Therefore, the angular frequency of the motion is 22.36 Hz.

b) To find the frequency (f) we can use the next equation:

$f = \frac{\omega}{2 \pi} = \frac{22.36 Hz}{2 \pi} = 3.56 Hz$

Hence, the frequency of the motion is 3.56 Hz.

c) The period (T) is equal to:

$T = \frac{1}{f} = \frac{1}{3.56 Hz} = 0.28 s$

Therefore, the period of the motion is 0.28 s.

I hope it helps you!

4 0

3 years ago