During the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

The velocity vector is always in the direction of motion of the object. So, during the ball's flight up its velocity vector is in the upward direction (90°) and during the ball's flight down its velocity vector is in the downward direction (270°).
When there is a positive acceleration in the object the acceleration vector is in the direction of motion of the object. When there is a negative acceleration in the object the acceleration vector is in the opposite direction of motion of the object. So, during the ball's flight up its acceleration vector is in the downward direction (270°) and during the ball's flight down its acceleration vector is in the upward direction (90°).

Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, during the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

To know more about velocity and acceleration vectors

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6 0

2 years ago

Which effects result from the influence of media and technology on children

Salsk061 [2.6K]

Can cause children into getting cyber bullying, being a thief, sexual behavior, anxiety, and depression

6 0

4 years ago

110-kg motorcycle and rider are traveling at 20 m/s. The rider notices a wreck ahead, applies the brakes, and manages to stop th

Tatiana [17]

To solve this problem it is necessary to apply the concepts related to the Conservation of Energy. Basically the work done on the body is equal to the existing change in kinetic energy. Mathematically this can be expressed as

$W = KE$

$F*d = \frac{1}{2} mv^2$

Where,

F = Force

d = Distance

m = Mass

v = Velocity

Our values are given as

d = 12m

m = 110kg

v = 20m/s

Replacing to find the force we have that,

$F*d = \frac{1}{2} mv^2$

$F*12 = \frac{1}{2} (110)(20)^2$

$F = 1833N$

Choosing the closest value, the correct answer would be E.

5 0

4 years ago

A person is standing on the beach counting the waves that come in. The person counts 10.0 waves in 68.0 s. What is the frequency

worty [1.4K]

Answer: 0.14 Hz

Explanation:

We are told the person counts 10 waves in 68 s, from this information we can calculate the frequency $f$ , which is defined as the number of oscilations or waves per unit of time. Then:

$f=\frac{10 waves}{68 s}$

$f=0.14 s^{-1}$

This is the frequency of the ocean waves. Now, according to the International System of Units (SI), frequency is measured in Hertz ( $Hz$ ), which is equivalent to $s^{-1}$ .

So, according to this, the frequency of the ocean waves is $f=0.14 Hz$

3 0

3 years ago