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Nadusha1986 [10]
3 years ago
12

A satellite originally moves in a circular orbit of radius R around the Earth. Suppose it is moved into a circular orbit of radi

us 4R. What happens to the satellite's speed?
Physics
2 answers:
noname [10]3 years ago
4 0

Answer:

The speed of satellite moving into circular orbit of radius 4R will become half of the speed of satellite moving into circular orbit of radius R.

Explanation:

Speed of satellite revolving around the central body in a circular path:

v=\sqrt{\frac{G\times M}{R}}

Where :

G = gravitational constant = 6.673 \times 10^{-11} Nm^2/kg^2]

M = Mass of body around which satellite is orbiting

R = radius of the orbit from the satellite

A satellite originally moves in a circular orbit of radius R around the Earth.The velocity of satellite will be ;

v=\sqrt{\frac{G\times M}{R}}..[1]

If the same satellite moves in a circular orbit of radius $R around the Earth.The speed of satellite will be :

v'=\sqrt{\frac{G\times M}{4R}}..[2]

Dividing [1] and [2]:

\frac{v}{v'}=\frac{\sqrt{\frac{G\times M}{R}}}{\sqrt{\frac{G\times M}{4R}}}

\frac{v}{v'}=2

v'=\frac{1}{2}v

The speed of satellite moving into circular orbit of radius 4R will become half of the speed of satellite moving into circular orbit of radius R.

sergiy2304 [10]3 years ago
3 0

 satellite originally moves in a circular orbit of radius R around the Earth. Suppose it is moved into a circular orbit of radius 4R.

(i) What does the force exerted on the satellite then become?

eight times larger<span>four times larger   </span>one-half as largeone-eighth as largeone-sixteenth as large(ii) What happens to the satellite's speed?<span>eight times larger<span>four times larger   </span>one-half as largeone-eighth as largeone-sixteenth as large(iii) What happens to its period?<span>eight times larger<span>four times larger   </span>one-half as largeone-eighth as largeone-sixteenth as large</span></span>
<span>
</span>
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