${x}^{2} + 25 = 0 \\ \therefore {x}^{2} = - 25 \\ \therefore {x} = \sqrt{ - 25} \\ \therefore {x} = \pm\sqrt{ - 1 \times 25} \\ \therefore {x} = \pm \sqrt{ 25} \times \sqrt{ - 1} \\ \therefore {x} = \pm5 \: i \\ \therefore {x} = \{ - 5i, \: \: 5i \} \: \\ is \: the \: solution \: set.$

7 0

3 years ago

Help please<br> will give brainliest

FromTheMoon [43]

The tangent line is perpendicular to the radius from the center of the circle to the point of tangency.
ΔDCE is similar to ΔDBA
DC/DB=DE/DA
15/50=DE/40
DE=12

3 0

3 years ago

Given a circle with a diameter of 4, what is the circumference?

Bezzdna [24]

Answer is B) 4 pi

Thank u

4 0

3 years ago

Read 2 more answers

Can someone help me on this question please

umka21 [38]

I THINK the answer is 5.