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3 years ago

A substance with a definite volume and a definite shape is classified as a what?

Chemistry

1 answer:

sergeinik [125]3 years ago

8 0

Answer:

Solids

Explanation:

It can be found

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Determine the overall reaction and its standard cell potential (in V) at 25°C for the reaction involving the galvanic cell made

mel-nik [20]

Answer:

Standard cell potential is 0.56V

Explanation:

Standard reduction potential ( $E^{0}$ ) are given below-

$E_{Cu^{+}\mid Cu}^{0}=0.52V$

$E_{Fe^{3+}\mid Fe}^{0}=-0.04V$

As $E_{Cu^{+}\mid Cu}^{0}$ is greater than $E_{Fe^{3+}\mid Fe}^{0}$ therefore Fe will be oxidized to $Fe^{3+}$ and $Cu^{+}$ will be reduced to Cu

Oxidation: $Fe(s)-3e^{-}\rightarrow Fe^{3+}(aq.)$

Reduction: $Cu^{+}(aq.)+e^{-}\rightarrow Cu(s)$

------------------------------------------------------------------------------------------------------

Overall: $Fe(s)+3Cu^{+}(aq.)\rightarrow Fe^{3+}(aq.)+3Cu(s)$

Standard cell potential, $E_{cell}^{0}=E_{Cu^{+}\mid Cu}^{0}-E_{Fe^{3+}\mid Fe}^{0}=(0.52+0.04)V=0.56V$

3 0

4 years ago

1. If a gas exerts a pressure of 2.00 atm when 20. puffs of particles are present, how many puffs are necessary to increase the

Juliette [100K]

Si un gaz exerce une pression de 2,00 atm lorsque 20 bouffées de particules sont présentes alors pour 4,50 atm il faut 45 bouffées car 20 bouffées = 2,00 atm donc 2*20=40 +0,5 =4,50

7 0

3 years ago

Calculate the percent composition by mass of each element in Al(OH)3. Use at least three significant figures.

motikmotik

Answer:

nope nope nope nope nope nope nope nope

7 0

3 years ago

Read 2 more answers

How many grams of 48.0 wt% NaOH (FM 40.00) should be diluted to 1.00 L to make 0.11 M NaOH? (Enter your answer using two digits.

kifflom [539]

Answer:

The answer is 916.67 g

Explanation:

48.0 wt% NaOH means that there are 48 g of NaOH in 100 g of solution. With this information and the molecular weight of NaOH (40 g/mol), we can calculate the number of mol there are in 100 g of this solution:

$\frac{48 g NaOH}{100 g solution}$ x $\frac{1 mol NaOH}{40 g}$ = 0.012 mol NaOH/100 g solution

Finally, we need 0.11 mol in 1 liter of solution to obtain a 0.11 M NaOH solution.

0.012 mol NaOH ------------ 100 g solution

0.11 mol NaOH------------------------- X

X= 0.11 mol NaOH x 100 g/ 0.012 mol NaOH= 916.67 g

We have to weigh 916.67 g of 48.0%wt NaOH and dilute it in a final volume of 1 L of water to obtain a 0.11 M NaOH solution.

7 0

3 years ago

What best describes the collisions between ideal gas molecules?

Serggg [28]

The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces. The more particles that hit the walls, the higher the pressure.

5 0

4 years ago