It will be the core of the atom surrounded by one electron cloud with two electrons the second electron cloud with the two other electrons will be omitted because those electrons were lost to give it a positive charge. electrons and protons come in equal numbers at most ground states and that is why. For periodic table however the proton count will always be the same count as the electrons.
Answer : The formula of the gas produced is,
(phosphine gas)
Explanation :
According to the question, when sodium phosphide is treated with water then it react to give phosphine gas and sodium hydroxide.
The balanced chemical reaction will be:
![Na_3P(aq)+3H_2O(l)\rightarrow PH_3(g)+3NaOH(aq)](https://tex.z-dn.net/?f=Na_3P%28aq%29%2B3H_2O%28l%29%5Crightarrow%20PH_3%28g%29%2B3NaOH%28aq%29)
By Stoichiometry of the reaction we can say that:
1 mole of sodium phosphide reacts with 3 moles of water to give 1 mole of phosphine gas and 3 moles of sodium hydroxide.
Thus, the formula of the gas produced is,
(phosphine gas)
<h2>
1.25 g of
would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
</h2>
Explanation:
To calculate the number of moles for given molarity, we use the equation:
![0.833M=\frac{\text{Moles of} HC_3H_3O_2\times 1000}{25ml}\\\\\text{Moles of} HC_3H_3O_2 =\frac{0.833mol/L\times 25}{1000}=0.0208mol](https://tex.z-dn.net/?f=0.833M%3D%5Cfrac%7B%5Ctext%7BMoles%20of%7D%20HC_3H_3O_2%5Ctimes%201000%7D%7B25ml%7D%5C%5C%5C%5C%5Ctext%7BMoles%20of%7D%20HC_3H_3O_2%20%3D%5Cfrac%7B0.833mol%2FL%5Ctimes%2025%7D%7B1000%7D%3D0.0208mol)
![NaHCO_3+HC_2H_3O_2\rightarrow NaC_2H_3O_2+H_2O+CO_2](https://tex.z-dn.net/?f=NaHCO_3%2BHC_2H_3O_2%5Crightarrow%20NaC_2H_3O_2%2BH_2O%2BCO_2)
According to stoichiometry:
1 mole of
will give = 1 mole of ![CO_2](https://tex.z-dn.net/?f=CO_2)
0.0208 moles of
will give =
of ![CO_2](https://tex.z-dn.net/?f=CO_2)
Mass of ![HC_2H_3O_2=moles\times {\text {molar mass}}=0.0208\times 60g/mol=1.25g](https://tex.z-dn.net/?f=HC_2H_3O_2%3Dmoles%5Ctimes%20%7B%5Ctext%20%7Bmolar%20mass%7D%7D%3D0.0208%5Ctimes%2060g%2Fmol%3D1.25g)
Thus 1.25 g of
would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
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Answer:
W = -262 J.
Explanation:
Hello there!
In this case, according to the given information, we can recall the definition of work in terms of constant pressure and variable volume as follows:
![W=P(V_2-V_1)](https://tex.z-dn.net/?f=W%3DP%28V_2-V_1%29)
So we plug in the given pressure and volumes to obtain:
![W=0.822atm(1.20L-4.35L)\\\\W=-2.60atm*L](https://tex.z-dn.net/?f=W%3D0.822atm%281.20L-4.35L%29%5C%5C%5C%5CW%3D-2.60atm%2AL)
Now, we convert this number to J (Pa*m³) by using the shown below conversion factor:
![W=-2.60atm*L*\frac{101325Pa}{1atm} *\frac{1m^3}{1000L}\\\\W=-262J](https://tex.z-dn.net/?f=W%3D-2.60atm%2AL%2A%5Cfrac%7B101325Pa%7D%7B1atm%7D%20%2A%5Cfrac%7B1m%5E3%7D%7B1000L%7D%5C%5C%5C%5CW%3D-262J)
Regards!
Yes. Everything is made up of mass. If it takes up space, it has mass