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mart [117]
3 years ago
6

Examine the graph at right. Then in a sentence suggest why the graph rises at 11:00am and drops at 1:15pm

Mathematics
1 answer:
makkiz [27]3 years ago
6 0
The x-axis of the graph is the time while y-axis of the given plot is the money inside Lucy's purse in dollars. we can see that from 6 am to 11 am, Lucy's money is equal to about $60 while around 11 am it rose up to around $125 and then decreased to $100. This means that in the given range of time, only one transaction per time range was done by Lucy. One scenario here was that before lunch, say 11 am, her money was $60 and found out that she has to buy something after work, in which her money was not enough. She went to withdraw some cash that's why she had $125 in total and has to spend a portion of it at lunch with the remaining cash of $100. 
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4vir4ik [10]
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4 0
3 years ago
Can I get some help on this question please
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3 0
2 years ago
Estimate the perimeter of the figure to the nearest whole number.
Paha777 [63]

Answer:

The perimeter (to the nearest integer) is 9.

Step-by-step explanation:

The upper half of this figure is a triangle with height 3 and base 6.  If we divide this vertically we get two congruent triangles of height 3 and base 3.  Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles:  (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.

Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.

The lower half of the figure has the shape of a trapezoid.  Its base is 4.  Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle.  Using the Pythagorean Theorem, we get

(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10.  Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.

Then the perimeter consists of the sum 2√10 + 4 + 6√2.

which, when done on a calculator, comes to 9.48.  We must round this off to the nearest whole number, obtaining the final result 9.

4 0
3 years ago
Paul wants to compare whether the prices of tangerines in two supermarkets differ significantly. He has been noting down the dai
Wewaii [24]
<span>Based on the rules of statistics</span>

 68% of the data falls within 1 standard deviation of the mean

95% of the data falls within 2 standard deviation of the mean

99% of the data falls within 3 standard deviation of the mean

 20 falls between the range of -56 to 56 (from the given 95%)

Hence we accept the null hypothesis; else, if the mean falls outside the range, we reject the null hypothesis.

<span> </span>

5 0
3 years ago
Jared bought a Suzuki 1000 for $12,698. If it depreciates at a rate of 11% per year, how much will it be worth in 3 years
Serga [27]
Original price = P = $12,698
Depreciation rate = r = 11% = 0.11
Time in years = t = 3
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The formula used will be:

A=P(1-r)^{t}

Using the values, we get:

A=12698(1-0.11)^{3}=8951.70

Thus, the worth of Suzuki after 3 years will be $8951.70
7 0
2 years ago
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