The scores on a test given to all juniors in a school district are normally distributed with a mean of 79 and a standard deviati
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A) you must plug in 50 for variable F and solve for C
C=
(50-32)
C=
(18)
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius
B) you must solve the equation for F
C=(F-32)
C/=F-32
C/+32=F
F= C/+32
dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as
F=
C +32
now you just plug in 50 for the variable C in the new equation
F=(50) +32
F= 90 + 32
F= 122
50 degrees celsius is equal to 122 degrees fahrenheit
hope this helped!
C=
C=
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius
B) you must solve the equation for F
C=
C/
C/
F= C/
dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as
F=
now you just plug in 50 for the variable C in the new equation
F=
F= 90 + 32
F= 122
50 degrees celsius is equal to 122 degrees fahrenheit
hope this helped!