Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K
Explanation :
We have to calculate the entropy change of reaction 
.
![\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo%3D%5Bn_%7BNH_3%7D%5Ctimes%20%5CDelta%20S%5E0_%7B%28NH_3%29%7D%5D-%5Bn_%7BN_2%7D%5Ctimes%20%5CDelta%20S%5E0_%7B%28N_2%29%7D%2Bn_%7BH_2%7D%5Ctimes%20%5CDelta%20S%5E0_%7B%28H_2%29%7D%5D)
where,
= entropy of reaction = ?
n = number of moles
= standard entropy of 
= standard entropy of 
= standard entropy of 
Now put all the given values in this expression, we get:
![\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo%3D%5B2mole%5Ctimes%20%28192.5J%2FK.mole%29%5D-%5B1mole%5Ctimes%20%28191.5J%2FK.mole%29%2B3mole%5Ctimes%20%28130.6J%2FK.mole%29%5D)
Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K
Answer:
Explanation:
Mass of F / Mass of S = 2.962/1 =2.962 X 32 / 32 = 94.78/32
Mass of F / Mass of S = 2.370 /1 = 2.370 X 32 / 32 = 75.84 /32
Mass of F /Mass of S = 3.555/1 = 3.555 x 32 / 32 = 113.76 / 32 .
Now constant mass of S that is 32 g reacts with different mass of F. They are as follows :
94.78 g , 75.84 g , and 113.76 g
Their ratio = 94.78 : 75.84 : 113.76
divide them by 19
their ratio = 5 : 4 : 6
So these data are consistent with law of multiple proportion.
Answer:
All the related answers are attached image formats...Regards
Answer:
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Explanation:
bzjzxbdjx dmxkemcneovmidc.kdncdjxndjxncjb
Answer:
Eukarya- Multicellar and unicellar
Explanation:
Fugi- Multicellar
Protista- unicellar
eubacteria- unicellar and have no nucleus
Eukarya is the only option, and that is because Eukarya is both! It contains a nucleus, and a membrane making it the only one that fits into the incomplete graphic! Hope this helps! (I noticed you were waiting for a while so I came to help! <3)
