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vazorg [7]
3 years ago
12

Why is it important to avoid consuming sugar?

Chemistry
1 answer:
GuDViN [60]3 years ago
3 0
As if the energy isn't burned off it turns into fat.
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Describe the relationship between temperature and pressure of a gas. Can you think of a real world example of this relationship?
jonny [76]
It is an proportional  relationship
 Pressure increases so does temperature and vice versa
7 0
3 years ago
What are the oxidation states of the atoms in a diatomic gas?
mafiozo [28]

Answer:

This is apparent charge, like water molecule is neutral having zero net charge

Explanation:

Simple and understood

4 0
3 years ago
The Henry's law constant for helium gas in water at 30 °C is 3.70 × 10-4 M/atm. When the partial pressure of helium above a samp
igor_vitrenko [27]

Answer:

The concentration of helium in the water is 2.405×10^-4 M

Explanation:

Concentration = Henry's law constant × partial pressure of helium

Henry's law constant = 3.7×10^-4 M/atm

Partial pressure of helium = 0.65 atm

Concentration = 3.7×10^-4 × 0.65 = 2.405×10^-4 M

4 0
3 years ago
How many moles are in 91.5 grams of Helium?
konstantin123 [22]

In order to find the number of moles with a given mass of Helium, we need to use its molar mass, which is 4.0026g/mol, therefore we will have:

4.0026g = 1 mol of Helium

91.5g = x moles of Helium

x = 22.86 moles of Helium in 91.5 grams

4 0
1 year ago
if 334.6 g of phosphoric acid is reacted with excess potassium hydroxide. the final mass K3PO4 produced is found to be 248g. wha
Orlov [11]

Answer:

                     %age Yield  =  34.21 %

Explanation:

                   The balance chemical equation for the decomposition of KClO₃ is as follow;

                            3 KOH + H₃PO₄ → K₃PO₄ + 3 H₂O

Step 1: Calculate moles of H₃PO₄ as;

Moles = Mass / M/Mass

Moles = 334.6 g / 97.99 g/mol

Moles = 3.414 moles

Step 2: Find moles of K₃PO₄ as;

According to equation,

                 1 moles of H₃PO₄ produces  =  1 moles of K₃PO₄

So,

              3.414 moles of H₃PO₄ will produce  =  X moles of K₃PO₄

Solving for X,

                      X = 1 mol × 3.414 mol / 1 mol

                      X = 3.414 mol of K₃PO₄

Step 3: Calculate Theoretical yield of K₃PO₄ as,

Mass = Moles × M.Mass

Mass = 3.414 mol × 212.26 g/mol

Mass = 724.79 g of K₃PO₄

Also,

%age Yield  =  Actual Yield / Theoretical Yield × 100

%age Yield  =  248 g / 724.79 × 100

%age Yield  =  34.21 %

3 0
3 years ago
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