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Sergio039 [100]
3 years ago
13

a snack that reginald just bought has 150 calories in 3/4 of a serving. how many calories per serving is this?

Mathematics
1 answer:
77julia77 [94]3 years ago
5 0
If there are 150 calories in 3/4 servings divide 150 by 3 and you get 50 ..you add 50 calories for the 1/4 servings which gives you 200 calories per serving
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Ana owns an airline and pays the airport $35.00 for each ticket sold. the amount Ana pays is given by f(x)=35x where x is the nu
nirvana33 [79]

Answer:

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Step-by-step explanation:

When dealing with real life, negative and imaginary numbers are not a possible answer.

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3 years ago
HELP!! <br> 9. What is the area of triangle AOB?
Akimi4 [234]

Angles ∠ACD and ∠CAB are congruent because they are alternate angles. Then the area of the triangle AOB will be 22.53 square cm.

<h3>What is the area of the right-angle triangle?</h3>

The area of the right-angle triangle is given as

A = 1/2 x B x H

Where B is the base and H is the height of the right triangle.

We know that angles ∠ACD and ∠CAB are congruent because they are alternate angles.

α₁ = 40°

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Then the area of the triangle will be

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Area = 22.53 square cm

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brainly.com/question/16653962

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5 0
1 year ago
Simplify the following expression.<br> 7x- 8+2x5x11
Alborosie

Answer:110x^2+7x-8

Step-by-step explanation:

7x- 8+2x5x11

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4 0
3 years ago
Find the volume of the composite figure. Explain your thought, explain how your arrived at your answer. SHOW YOUR WORK FOR FULL
kobusy [5.1K]
We assume the composite figure is a cone of radius 10 inches and slant height 15 inches set atop a hemisphere of radius 10 inches.

The formula for the volume of a cone makes use of the height of the apex above the base, so we need to use the Pythagorean theorem to find that.
   h = √((15 in)² - (10 in)²) = √115 in

The volume of the conical part of the figure is then
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The volume of the hemispherical part of the figure is given by
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Then the total volume of the figure is
   V = (volume of conical part) + (volume of hemispherical part)
   V = (100π√115)/3 in³ + 2000π/3 in³
   V = (100π/3)(20 + √115) in³
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