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GarryVolchara [31]
3 years ago
8

The amount of Jen’s monthly phone bill is normally

Mathematics
1 answer:
vredina [299]3 years ago
7 0

Answer:

P(19

And we can find this probability with this difference and using the normal standard distribution

P(-3

Step-by-step explanation:

Let X the random variable that represent the amount of Jen monthly phone of a population, and for this case we know the distribution for X is given by:

X \sim N(55,12)  

Where \mu=55 and \sigma=12

We are interested on this probability

P(19

And we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

Replacing the info we got:

P(19

And we can find this probability with this difference and using the normal standard distribution

P(-3

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