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3 years ago

The amount of Jen’s monthly phone bill is normally

Mathematics

1 answer:

vredina [299]3 years ago

7 0

Answer:

$P(19$

And we can find this probability with this difference and using the normal standard distribution

$P(-3$

Step-by-step explanation:

Let X the random variable that represent the amount of Jen monthly phone of a population, and for this case we know the distribution for X is given by:

$X \sim N(55,12)$

Where $\mu=55$ and $\sigma=12$

We are interested on this probability

$P(19$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

Replacing the info we got:

$P(19$

And we can find this probability with this difference and using the normal standard distribution

$P(-3$

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Don’t understand. Pls explain :)

sveta [45]

Step-by-step explanation:

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3 years ago

PLS HELP:

____ [38]

1) At 95% Confidence interval the critical value is z0.025= 1.96 Margin of error = 0.02 Or, z0.025* sqrt(p(1 - p)/n) = 0.02 Or, 1.96 * sqr

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2 years ago

Read 2 more answers

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$

Then

$\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.$

Answer 2: correct choice is D.

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3 years ago

Read 2 more answers

Mr. Walker is looking at the fundraiser totals for the last five years.

klemol [59]

Answer:

the median is $1.60 greater than the mean

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2 years ago

PLEASE HELP IM STUCK. <br><br> List the factors of the third term: 6n^3-n^2+5n/8-11

mafiozo [28]

Answer:

The factors for 5 are going to be 1 and 5 or their negative counterparts, since no other whole number within the range of 5 can be multiplied to get 5.

Make sense?

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3 years ago