Find the domain of f(x)= sqrt2-9x

Mathematics

1 answer:

victus00 [196]3 years ago

5 0

f(x) = $\sqrt{2 - 9x}$

2 - 9x ≥ 0

- 9x ≥ - 2

$\frac{-9x}{-9} \geq \frac{-2}{-9}$

x ≤ $\frac{2}{9}$

Interval Notation: (-∞, $\frac{2}{9}$ ]

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