Question

Find the domain of f(x)= sqrt2-9x

Answer 1

f(x) = $\sqrt{2 - 9x}$

2 - 9x ≥ 0

  - 9x ≥ - 2

     $\frac{-9x}{-9} \geq \frac{-2}{-9}$

     x ≤ $\frac{2}{9}$

Interval Notation: (-∞, $\frac{2}{9}$]