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Charra [1.4K]
4 years ago
6

Find the domain of f(x)= sqrt2-9x

Mathematics
1 answer:
victus00 [196]4 years ago
5 0

f(x) = \sqrt{2 - 9x}

2 - 9x ≥ 0

  - 9x ≥ - 2

     \frac{-9x}{-9} \geq \frac{-2}{-9}

     x ≤ \frac{2}{9}

Interval Notation: (-∞, \frac{2}{9}]

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