PWC operators must keep in mind that a jet drive needs moving water through the drive nozzle for maneuverability. In other term, you must have power applied in order to uphold steering control. If the engine shuts off during operation or If you release the throttle to idle, you will lose all steering control. In either situation, the PWC will remain in the direction it was headed before the throttle was released or the engine was shut off. Action of the steering control will have no outcome. If you are approaching a dock, shore, or other vessel at a speed bigger than you can control and you release the throttle to idle or shut off the engine, you won’t have maneuvering capability and the PWC will stay its forward movement.
The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.
At time 
, the acceleration vector has direction 
such that
which indicates the particle is situated at a point on the lower left half of the circle, while at time 
the acceleration has direction 
such that
which indicates the particle lies on the upper left half of the circle.
Notice that 
. That is, the measure of the major arc between the particle's positions at and is 270 degrees, which means that 
is the time it takes for the particle to traverse 3/4 of the circular path, or 3/4 its period.
Recall that
where 
is the radius of the circle and 
is the period. We have
and the magnitude of the particle's acceleration toward the center of the circle is
So we find that the path has a radius of
The power that heat pump draws when running will be 6.55 kj/kg
A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).
Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8
We have to determine the power the heat pump draws when running.
To solve this question we have to assume that the heat pump is at steady state
Let,
Q₁ = 22000 kj/kg
COP = 2.8
Since heat pump used to heat a house runs about one-third of the time.
So,
Q₁ = 3(22000) = 66000 kj/kg
We known the formula for cop of heat pump which is as follow:
COP = Q₁/ω
2.8 = 66000 / ω
ω = 66000 / 2.8
ω = 6.66 kj/kg
Hence the power that heat pump draws when running will be 6.55 kj/kg
Learn more about heat pump here :
brainly.com/question/1042914
#SPJ4
Explanation:
In 1897, J.J. ... Thomson realized that the accepted model of an atom did not account for negatively or positively charged particles. Therefore, he proposed a model of the atom which he likened to plum pudding. The negative electrons represented the raisins in the pudding and the dough contained the positive charge.
