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jasenka [17]
3 years ago
6

A car travels at a speed of 30 mph. how far does the car travel in 2 hours

Physics
1 answer:
Travka [436]3 years ago
3 0

Answer:

The car would travel <u>60 miles</u> in 2 hours.

Explanation:

The distance for an hour is already given, 30 <u>miles per hour</u>.

Given this you could multiply 30 by 2 which gives you <u>60</u>.

You might be interested in
What is the period of a sound wave having a frequency of 340 Hz
sertanlavr [38]

Answer:

lambda = 343 m/s divided by 340 Hz = 1.009 seconds

Hope it helps and have a wonderful day!

4 0
2 years ago
Read 2 more answers
Which option lists a form of potential energy followed by a form of kinetic energy?
Nadusha1986 [10]

Answer:

Magnetic energy and electromagnetic energy form of potential energy followed by a form of kinetic energy.

(B) is correct option.

Explanation:

Given that,

Lists a form of potential energy followed by a form of kinetic energy

We know that,

Sound energy :

The movement of energy through object it is called sound energy. When a object produced vibration by force then it moves in wave.

Sound wave is example of kinetic energy.

Nuclear energy :

The store energy in the nucleus of the atom it is called nuclear energy. This energy released when occurs fusion and fission.

Nuclear energy is the example of potential energy

Magnetic energy :

Magnetic energy is a type of potential energy which is depend on distance and position in the magnetic field.

Electromagnetic energy :

Electromagnetic energy is light energy. it is type of kinetic energy.

Gravitational energy :

Gravitational energy is a type of potential energy. It is an energy related with gravity or gravitational force.

Elastic energy :

The store energy in elastic object it is called elastic energy. This energy is a type of potential energy.

Electrical energy :

The movement of electrons is called electrical energy. When electrons move through a wire then it is are called electricity. Electrical energy is type of kinetic energy.

Hence, Magnetic energy and electromagnetic energy form of potential energy followed by a form of kinetic energy.

(B) is correct option.

4 0
3 years ago
Read 2 more answers
Jack and Jill have made up since the previous HW assignment, and are now playing on a 10 meter seesaw. Jill is sitting on one en
Airida [17]

Answer: 3 m.

Explanation:

Neglecting the mass of the seesaw, in order the seesaw to be balanced, the sum of the torques created by  gravity acting on both children  must be 0.

As we are asked to locate Jack at some distance from the fulcrum, we can take torques regarding the fulcrum, which is located at just in the middle of the length of the seesaw.

If we choose the counterclockwise direction as positive, we can write the torque equation as follows (assuming that Jill sits at the left end of the seesaw):

mJill* 5m -mJack* d = 0

60 kg*5 m -100 kg* d =0

Solving for d:

d = 3 m.

6 0
3 years ago
A felt-covered beanbag is fired into a empty wooden crate that sits on a concrete floor and is open on one side. The beanba
Phantasy [73]

Answer:

31.42383 m/s

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

\mu = Coefficient of kinetic friction = 0.48

s = Displacement = 0.935 m

m_1 = Mass of bean bag = 0.354 kg

m_2 = Mass of empty crate = 3.77 kg

v_1 = Speed of the bean bag

v_2 = Speed of the crate

Acceleration

a=-\frac{f}{m}\\\Rightarrow a=-\frac{\mu mg}{m}\\\Rightarrow a=-\mu g

a=--9.81\times 0.48=4.7088\ m/s^2

From equation of motion

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.7088\times 0.935+0^2}\\\Rightarrow v=2.96739\ m/s

In this system the momentum is conserved

m_1v_1=(m_1+m_2)v_2\\\Rightarrow v_1=\frac{(m_1+m_2)v_2}{m_1}\\\Rightarrow u=\frac{(0.354+3.77)\times 2.69739}{0.354}\\\Rightarrow u=31.42383\ m/s

The speed of the bean bag is 31.42383 m/s

8 0
3 years ago
Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. Part A If the surfac
alukav5142 [94]

Answer:

5308.34 N/C

Explanation:

Given:

Surface density of each plate (σ) = 47.0 nC/m² = 47\times 10^{-9}\ C/m^2

Separation between the plates (d) = 2.20 cm

We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:

E=\dfrac{\sigma}{2\epsilon_0}

Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,

E_{between}=E+E=2E=\frac{2\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}

Now, plug in  47\times 10^{-9}\ C/m^2 for 'σ' and 8.85\times 10^{-12}\ F/m for \epsilon_0 and solve for the electric field. This gives,

E_{between}=\frac{47\times 10^{-9}\ C/m^2}{8.854\times 10^{-12}\ F/m}\\\\E_{between}= 5308.34\ N/C

Therefore, the electric field between the plates has a magnitude of 5308.34 N/C

5 0
2 years ago
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