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fgiga [73]
4 years ago
6

The chemical combination of two or more different atoms in fixed amounts is called a(n)

Physics
2 answers:
Alisiya [41]4 years ago
6 0

its a compound because it is form by the chemical combination of two or more elements.

amid [387]4 years ago
4 0
Its a compound because the chemical combination of two or more different atoms in fixed amounts is a compund

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A boy at a football field practice kicked a 0.500-kg ball with a force of 100N. How fast will the ball move after reaching a dis
Tpy6a [65]

Answer:

v(7) = 52.915 m/s

Explanation:

First, find the value for acceleration.

F = ma

100 = .5 * a

a = 200 m/s²

Next find the velocity at x = 7 using kinematic equations.

v² = v₀² + 2a(Δx)

v² = (0)² + 2(200)(7)

v = \sqrt{2800}

v = 52.915 m/s

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3 years ago
What is the area under the curve for the histogram below
igor_vitrenko [27]

Answer:  B srry if i'm wrong

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2 years ago
a lamp hangs from the ceiling at the height of 2.9 m. if the lamp breaks and falls to the floor what is its impact speed
nydimaria [60]
This is a problem that can be solved using free-fall motion analysis. Since the displacement (2.9m) is given, we can use the following equation to solve for the impact speed:

V^2 = 2gh

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4 years ago
This is for science ill give you brainliest
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The golf ball represents the solar system and the football represents the Milky Way. Our solar system is <em>a lot</em> smaller than the Milky Way, just like how a golfball is smaller than a football.

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3 years ago
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- The school zone in front of your school has a posted speed limit of 25 mi/h, which is about 11 m/s. Let's
miv72 [106K]

Answer:

s = 38.7 m

Explanation:

First we calculate the distance covered during uniform motion of reaction time.

s₁ = vt

where,

s₁ = distance covered during uniform motion = ?

v = uniform speed = 11 m/s

t = time = 2.3 s

Therefore,

s₁ = (11 m/s)(2.3 s)

s₁ = 25.3 m

Now, we calculate the distance covered during decelerated motion:

2as₂ = Vf² - Vi²

where,

a = deceleration = -4.5 m/s²

s₂ = distance covered during decelerated motion = ?

Vf = Final Velocity = 0 m/s

Vi = Initial Velocity = 11 m/s

Therefore,

2(-4.5 m/s²)s₂ = (0 m/s)² - (11 m/s)²

s₂ = (-121 m²/s²)/(-9 m/s²)

s₂ = 13.4 m

the total distance will be:

s = s₁ + s₂

s = 25.3 m + 13.4 m

<u>s = 38.7 m</u>

5 0
3 years ago
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