A closed system contains 30g of gas. How much heat(in joules) is added to or rejected by the system to produce 5000 N-m of work
1 answer:
Answer : The heat rejected by the system is 1000 J
Explanation :
As per first law of thermodynamic,
where,
= internal energy of the system
q = heat added or rejected by the system
w = work done of the system
First we have to determine the internal energy for 30 grams of gas.
As, 1 gram of gas has internal energy = 200 J
So, 30 grams of gas has internal energy = 200 × 30 = 6000 J
Now we have to determine the heat of the system.
= -6000 J
w = 5000 N.m = 5000 J
Now put all the given values in the above formula, we get:
The negative sign indicate that the heat rejected by the system.
Hence, the heat rejected by the system is 1000 J
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Answer:
a) The proton's speed is 5.75x10⁵ m/s.
b) The kinetic energy of the proton is 1723 eV.
Explanation:
a) The proton's speed can be calculated with the Lorentz force equation:
(1)
Where:
F: is the force = 9.14x10⁻¹⁷ N
q: is the charge of the particle (proton) = 1.602x10⁻¹⁹ C
v: is the proton's speed =?
B: is the magnetic field = 3.28 mT
θ: is the angle between the proton's speed and the magnetic field = 17.6°
By solving equation (1) for v we have:
Hence, the proton's speed is 5.75x10⁵ m/s.
b) Its kinetic energy (K) is given by:
Where:
m: is the mass of the proton = 1.67x10⁻²⁷ kg
Therefore, the kinetic energy of the proton is 1723 eV.
I hope it helps you!