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Ludmilka [50]
3 years ago
15

A stockroom worker pushes a box with mass 11.2 kg on a horizontal surface with constant speed of 3.50m/s. The coefficient of kin

etic friction between the box and the surface is 0.20.
What horizontal force must the worker apply to maintain the motion(Answer in N)?
If the force in the previous part is removed, how far does the box slide before coming to rest(Answer in m)?
Physics
1 answer:
stellarik [79]3 years ago
4 0

Answer:

3.125 m

Explanation:

We are given that

Mass of box=m=11.2 kg

Speed of box=u=3.5m/s

Coefficient of kinetic friction=\mu_k=0.2

Final velocity,v=0

a.We have to find the horizontal force applied by worker to maintain the motion.

According to question

Horizontal force=F=f=\mu_kmg

g=9.8m/s^2

Substitute the values

Horizontal force=F=0.2\times 11.2\times 9.8=21.95 N

b.According to work-energy theorem

W=\frac{1}{2}mv^2-\frac{1}{2}mu^2

-\mu mg s=\frac{1}{2}(11.2)(0)^2-\frac{1}[2}(11.20)(3.5)^2

-\mu mg s=-\frac{1}{2}(11.2)(3.5)^2

0.2\times (11.2)\times 9.8\times s=\frac{1}{2}(11.2)(3.5)^2

s=\frac{11.2\times (3.5)^2}{2\times 0.2\times 11.2\times 9.8}

s=3.125 m

Hence, the box slide before coming to rest=3.125 m

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A reasonable estimate for the height of the walls in an ordinary american home is?
Olegator [25]

A reasonable estimate for the height of the walls in an ordinary American home is 2.5m.

<h3>What is wall estimation?</h3>

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8 0
1 year ago
Un neumático sin cámara, soporta una presión de 1.5 atm cuando la temperatura ambiente es de 300°K. ¿Qué presión llegará a sopor
arlik [135]

Answer:

El neumático soportará una presión de 1.7 atm.

Explanation:

Podemos encontrar la presión final del neumático usando la ecuación del gas ideal:

PV = nRT

En donde:

P: es la presión

V: es el volumen

n: es el número de moles del gas

R: es la constante de gases ideales

T: es la temperatura

Cuando el neumático soporta la presión inicial tenemos:

P₁ = 1.5 atm

T₁ = 300 K

V_{1} = \frac{nRT_{1}}{P_{1}}  (1)  

La presión cuando T = 67 °C es:

P_{2} = \frac{nRT_{2}}{V_{2}}   (2)

Dado que V₁ = V₂  (el volumen del neumático no cambia), al introducir la ecuación (1) en la ecuación (2) podemos encontrar la presión final:

P_{2} = \frac{nRT_{2}}{V_{2}} = \frac{nRT_{2}}{\frac{nRT_{1}}{P_{1}}} = \frac{P_{1}T_{2}}{T_{1}} = \frac{1.5 atm*(67 + 273)K}{300 K} = 1.7 atm  

Por lo tanto, si en el transcurso de un viaje las ruedas alcanzan una temperatura de 67 ºC, el neumático soportará una presión de 1.7 atm.

Espero que te sea de utilidad!

4 0
3 years ago
HEY CAN YALL PLS HELP ME IN DIS!!!!!!!!!!!!!
Serga [27]

Answer:

Hey!!

Your answer is: 0.72

Explanation:

if 760=1  then...

550=x

=550÷760= 0.72 in two s.f

6 0
3 years ago
In February 1955, a paratrooper fell 365 m from an airplane without being able to open his chute but happened to land in snow, s
DaniilM [7]

Answer:

a. i=4760 kg*m/s

b. D_U= 1.11 m

Explanation:

a)

F= 120,000N

Kinetic energy @ impact = 120,000*depth

K_E= (1/2)*85kg*(56m/s)^2

K_E=133280 J

D_U= \frac{133280J}{120000N} = 1.11 m

b)

The momentum is equal to the impulse on him from the snow so:

p=m*v

p=85kg*56m/s

i=4760 kg*m/s

7 0
3 years ago
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