In this scenario we know that carbon14 at a given time A(t) = A0e^(-kt), where A0 is the original carbon present, t is time in years and k is the constant.
As we are working with the half life of carbon being 5730 years, we assume original carbon-14 content, A0 = 1, and carbon-14 at half life 5730 years, A(t) = 0.5.
i.e.
0.5 = 1e^(-5730k)
apply Ln to both sides of equation to cancel e
ln(0.5) = -5730k
k = ln(0.5) / -5730
k = -0.69315 / - 5730 = 1.20968 x 10^-4
Hello!
First you find how far he went
So he we 96 kilometers there and back
96 + 96 = 192
It took him 8 hours to go 192 kilometers
To find the average speed you divide these two
192/8 = 24
So his average speed was 24 kilometers an hour
The answer is 24
Hope this helps!
1inch = 2.5cm
∆ 30cm
<h3>1inch x 30cm \2.5cm =? </h3>
5cm =2inch
- so 30cm=12inch
Answer:
B.
Step-by-step explanation:
y = 3/4x + 2 slope: 3/4
perpendicular line slope: - 4/3
