What exactly is we supposed to do?
I'll answer it after u answer my question
Answer:
Step-by-step explanation:
here is some helpful trig function reminders.. copy this and keep it
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
they ask how long is the ladder
they give us the opposite side (8) and the adjacent side (6)
and the Hyp is the length of the ladder. They expect you to sort this out in your head. :/
there is two steps .. we'll solve for the angle.. then we can use that to find the Hyp side..(long side of triangle) which is the ladder length
Tan(Ф) = Opp / Adj
Tan(Ф) = 8 / 6
Ф = arcTan(8 / 6)
Ф ≈ 53.130°
now lets use that angle with one of the other trig functions to find the Hyp.. sin or cos will work b/c we have both the opp and the adj sides lengths. let's use cos
Cos(53.130) = 6 / Hyp
Hyp = 6 / Cos(53.130) ( I just used algebra to swap the two)
Hyp = 9.99997
the ladder will be 10' long.
ask in the comments if you need any more explaining
We want to study a general product, and find information about the ones place.
We will see that the ones place is always zero.
We have the expression:
10×?
Where ? can be any number between 1 and 9 (only whole ones)
What is true about the digit of the ones place (the first digit at the left of the decimal point) in each product?
Let's give ? some different values and see what happens:
10×1 = 10
10×2 = 20
10×3 = 30
etc...
We can see that the ones place will always be equal to zero.
If you want to learn more, you can read:
brainly.com/question/16552177
Z/70over30................
X= 130°
Step-by-step explanation:
From E, draw EF || AB || CD.
Now, EF || CD and CE is the transversal.
So; <DCE + <CEF = 180° [co. int. <s]
x° + <CEF = 180°
<CEF = (180° – x°).
Again, EF || AB and AE is the transversal.
So; <BAE + <AEF = 180° 01 [co. int. <s ]
105° + <AEC+ <CEF = 180°
105° +25° + (180° – x°) = 180°
x° = 130°
I hope I helped you^_^
