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blsea [12.9K]
3 years ago
11

Multiples of 6 are also multiples of 3

Mathematics
2 answers:
irakobra [83]3 years ago
7 0

12, 18, 24 that should be all

Black_prince [1.1K]3 years ago
5 0

Answer:

(☞゚ヮ゚)☞

Step-by-step explanation:

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Please help!! Will give brainiest!1 Im so confused
Lubov Fominskaja [6]

Answer:

i dont know

Step-by-step explanation:

5 0
3 years ago
One postive interger is 5 less than another. The product of the two intergerd id 24. What are the intergers?
Nesterboy [21]
Your function will be 24=X+(Y+5)

to solve you subtract 5 from each side giving you 19=X+Y now you divide the 19 by 2 so you figure out the base integers giving you 9.5

now you add 5 to one of your integers meaning 9.5+5=14.5

so your integers are 9.5 and 14.5

to check this you do 14.5-9.5 which equal 5 now you do 14.5+9.5 which equals 24
4 0
3 years ago
the pearl restaurant put a larger aquarium in its lobby. the base is 6 ft by 3 ft and the height is 4 ft how many more cubic fee
Anit [1.1K]
Well 6×12=72. I don't know what the original tank size was but subtract the original from this one to get your answer.
6 0
3 years ago
How do you find the equation of a triangles altitude using point slope formula?
forsale [732]
<span><span><span>1. An altitude of a triangle is a line segment from a vertex perpendicular to the opposite side. Find the equations of the altitudes of the triangle with vertices (4, 5),(-4, 1) and (2, -5). Do this by solving a system of two of two of the altitude equations and showing that the intersection point also belongs to the third line. </span>
(Scroll Down for Answer!)</span><span>Answer by </span>jim_thompson5910(34047)   (Show Source):You can put this solution on YOUR website!
<span>If we plot the points and connect them, we get this triangle: 

 

Let point 
A=(xA,yA)
B=(xB,yB)
C=(xC,yC) 



------------------------------- 
Let's find the equation of the segment AB 


Start with the general formula 

 


Plug in the given points 

 


Simplify and combine like terms 

 


So the equation of the line through AB is  


------------------------------- 
Let's find the equation of the segment BC 


Start with the general formula 

 


Plug in the given points 

 


Simplify and combine like terms 

 


So the equation of the line through BC is  




------------------------------- 
Let's find the equation of the segment CA 


Start with the general formula 

 


Plug in the given points 

 


Simplify and combine like terms 

 


So the equation of the line through CA is  




So we have these equations of the lines that make up the triangle 


 



So to find the equation of the line that is perpendicular to  that goes through the point C(2,-5), simply negate and invert the slope  to get 

Now plug the slope and the point (2,-5) into  


 

 Solve for y and simplify 

So the altitude for vertex C is  



Now to find the equation of the line that is perpendicular to  that goes through the point A(4,5), simply negate and invert the slope to get  

Now plug the slope and the point (2,-5) into  


 

 Solve for y and simplify 

So the altitude for vertex A is  




Now to find the equation of the line that is perpendicular to  that goes through the point B(-4,1), simply negate and invert the slope to get  

Now plug the slope and the point (-4,1) into  


 

 Solve for y and simplify 

So the altitude for vertex B is  



------------------------------------------------------------ 
Now let's solve the system 


 

 Plug in  into the first equation 

 Add 2x to both sides and subtract 2 from both sides 

 Divide both sides by 3 to isolate x 


Now plug this into  

 

 



So the orthocenter is (-2/3,1/3) 

So if we plug in  into the third equation , we get 


 


 


 

 

So the orthocenter lies on the third altitude 





</span><span>
</span></span>
3 0
3 years ago
PLS HELP ASAP If -2 is added to each of the x and y intercepts of the line 3x + 2y = 6, find the new equation of the line
ella [17]

Answer:

3x + 2y = -4

Step-by-step explanation:

x intercept of the line occurs at y = 0

Given the equation 3x+2y = 6

3x+2(0) = 6

3x  = 6

x = 2

The x intercept is at (2, 0)

Adding -2 to each axis will give (2-2, 0-2) = (0, -2)

y intercept of the line occurs at x = 0

Given the equation 3x+2y = 6

3(0)+2y = 6

2y  = 6

y =3

The x intercept is at (0, 3)

Adding -2 to each axis will give (0-2, 3-2) = (-2, 1)

The new coordinates are (0, -2 and (-2, 1)

Using the point slope form of the equation y - y0 = m(x-x0)

slope m = y2-y1/x2-x1

m = 1-(-2)/-2-0

m = 1+2/-2

m = -3/2

Using m = -3/2 and (0, -2)

y - (-2) = -3/2(x-0)

y+2 = -3/2 x

2(y+2) = -3x

2y+4 = -3x

-3x-2y = 4

3x + 2y = -4

Hence the required equation is 3x + 2y = -4

7 0
2 years ago
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