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4 years ago

Which choice best characterizes K+ leakage channels? View Available Hint(s)

Physics

1 answer:

hoa [83]4 years ago

7 0

Answer:

C. <u>Trans-membrane protein channels that are always open to allow K+ to cross the membrane without the additional input of energy</u>

Explanation:

As we know that K+ leakage channels indicate the Potassium leakage channel. The best characterizes about K+ leakage channels is that there is a Trans-membrane protein channel which is always open to allow K+ to cross the membrane without the additional input of energy.

Actually when a cell dies its membrane potential gets more positive and finally reaches zero .

The key point is that the cells spend energy to maintain the intra-cellular ionic concentrations constant.

The membrane permeability of K+ is much higher than the membrane permeability of Na+.

Therefore, the correct choice is option (C).

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Suppose that you make a series RC circuit with a capacitor and a known resistor that has a 5% tolerance: R= 5.20 ± 0.26kΩ. You p

Masja [62]

Answer:

correct answer is C

Explanation:

The time constant of an RC circuit is

τ = RC

so to find the capacitance

C = τ/ R

C = 2.150 / 5.20 10³

C = 4.13 10⁻⁴ F

to find the error we use the worst case

ΔC = | $|\frac{dC}{d \tau }| \ \Delta \tau + | \frac{dC}{dR} | \ \Delta R$

the absolute value guarantees that we find the worst case, we evaluate the derivatives

ΔC = 1 /R Δτ + τ/R² ΔR

the absolute values of the errors are

Δτ = 0.002 s

ΔR = 0.3 kΩ

we substitute

ΔC = 0.002 /5.20 10³ + 2.150/(5.20 10³)² 0.3 10³

ΔC = 3.8 10⁻⁷ + 1.74 10⁻⁵

ΔC = 1.77 10⁻⁵ F

the uncertainty or error must be expressed with a significant figure

ΔC = 2 10⁻⁵ F

the percentage error is

Er% = $\frac{\Delta C}{C} \ 100$

Er% = $\frac{2 \ 10^{-5} }{ 4.13 \ 10^{-4} } \ 100$

Er% = 4.8%

the correct answer is C

3 0

3 years ago

A 1.4kg ball is swung in a vertical circle with a radius of 0.8m. If the frequency is 1.5Hz, find the tension in the rope at the

Artyom0805 [142]

Answer:

Explanation:

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3 years ago

A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while

marta [7]

Answer:

Explanation:

Energy stored in a parallel plate capacitor is given by:

$U=\frac{1}{2}CV^2\\\\C=\frac{A\epsilon_{o}}{d}\\\\then\\\\U=\frac{1}{2}\frac{A\epsilon_{o}}{d}V^2--(1)\\\\$

As capacitor remains connected to the battery so V remains constant. As can be seen from (1) that energy is inversely proportional to the separation between the plates so as 'd' becomes doubled, energy decreases by the factor of 2.

3 0

3 years ago

Read 2 more answers

A loaded 320 kg toboggan is traveling on smooth horizontal snow at 4.60 m/s when it suddenly comes to a rough region. The region

MariettaO [177]

Answer:

367.04 N

Explanation:

Frictional force = mass of the toboggan×deceleration caused by the rough region

Fr = m×ar....................... Equation 1

Where Fr = Average frictional force, m = mass of loaded toboggan, ar = deceleration cause by the rough region.

We can calculate for ar using the formula below

v² = u²+2ars................... Equation 2

make ar the subject of the equation

ar = (v²-u²)/2s.................. Equation 3

Where v = final velocity of the toboggan, u = initial velocity of the toboggan, s = distance or length of the rough region

Given: v = 1.2 m/s, u = 4.6 m/s, s = 8.6 m

Substitute into equation 3

ar = (1.2²-4.6²)/(2×8.6)

ar = (1.44-21.16)/17.2

ar = -19.72/17.2

ar = -1.147 m/s²

Also given: m = 320 kg

Substitute into equation 1

Fr = 320(-1.147)

Fr = -367.04 N

Note: The negative sign tells that the frictional force opposes the motion of the toboggan

6 0

3 years ago

A clarinetist, setting out for a performance, grabs his 3.230 kg3.230 kg clarinet case (including the clarinet) from the top of

SpyIntel [72]

Answer:

- 0.5 m/s²

Explanation:

m = mass of the clarinet case = 3.230 kg

W = weight of the clarinet case in downward direction

a = vertical acceleration of the case

Weight of the clarinet case is given as

W = mg

W = 3.230 x 9.8

W = 31.654 N

F = Upward force applied = 30.10 N

Force equation for the motion of the case is given as

F - W = ma

30.10 - 31.654 = 3.230 a

a = - 0.5 m/s²

8 0

3 years ago