The time taken for the arrow to hit the ground is 0.53 s.
The horizontal distance traveled by the arrow is 25.97 m.
The given parameters:
- Initial horizontal velocity,
= 49 m/s - Initial vertical velocity,
= 0
<h3>What is time of motion?</h3>
- This is the time taken for a projectile to land on the plane of projection.
The time of motion is calculated as follows;
The horizontal distance traveled by the arrow is calculated as follows;
Learn more about time of motion here: brainly.com/question/2364404
Answer:
average speed is 0.159 m/s
average velocity = 0.0011 m/s
Explanation:
given data
time = 41.6 s
total distance = 6.65 m
length = 0.0463 m
to find out
average speed and the magnitude average velocity
solution
we know average speed formula is
average speed = 
...............1
put here value
average speed = 
average speed is 0.159 m/s
and
average velocity formula is
average velocity = 
...............2
here displacement is initial point to final point and here is 0.0463 m
put here value
average velocity = 
average velocity = 0.0011 m/s
Answer:B
Explanation:
Initial velocity, u=0m/s
Distance,s=20m
a=+g=9.8m/s*s
Using v*v=u*u+2gs
v*v=0+2*9.8*20
v*v=392
v=19.8
When s=20m, v = 19.8m/s
Therefore when v = 10m/s, s= 10*20/19.8
s =10.1m
If he stops running the tea is still going to be moving so it will spill on him.
