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chubhunter [2.5K]
3 years ago
15

The Japanese 5 yen coin has a hole in the middle. The diameter of the coin is 22 mm and the diameter of the hole is 5 mm. What i

s the difference between the outer edge and the inner edge of the coin? If necessary, round your answer to the nearest tenth.
26.7 mm
53.4 mm
69.1 mm
84.8 mm
Mathematics
2 answers:
Greeley [361]3 years ago
8 0
The answer to this question is 53.4.
VMariaS [17]3 years ago
5 0

Answer:

To find the difference between the outer and inner edges of the coin, you would calculate the circumference of the coin, C= 22π, and the circumference of the hole, C = 5π. Then you would subtract to find the answer, 22π − 5π = 17π.

Step-by-step explanation:

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Mkey [24]
Area of semicircle = 1/2 the area of a circle:
A_{sc}=\frac{1}{2}  \pi  r^{2}
radius is half the diameter of 6ft.
A_{sc} = \frac{1}{2}  \pi  (3^{2} )=14.13 ft^{2} .
Area of the rectangle:
A_{r} =lw=15*6=90 ft^{2} .
Add the two together:
90 + 14.13 = 104.13
Round to the nearest tenth (one decimal place)
Area = 104.1 square feet.

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4 years ago
What is the domain if the function on the graph? please help
Daniel [21]
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3 years ago
Need help with this please
Katarina [22]

Answer:

The third side is sqrt(77)

Step-by-step explanation:

Since this is a right triangle we can use the Pythagorean theorem

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5 0
4 years ago
Which of the follow expressions are equivalent to (3^4)^-2 • (3^5)^3
Fiesta28 [93]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Error Analysis: Pedro compares 7/33 and 2/11. He incorrectly says 7/33 < 2/11 because 4.71 < 5.50. Compare 7/33 and 2/11.
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