Answer:
4
Step-by-step explanation:
(6^2) -5(6) -2 =4
that is the answer
<u>We'll assume the quadratic equation has real coefficients</u>
Answer:
<em>The other solution is x=1-8</em><em>i</em><em>.</em>
Step-by-step explanation:
<u>The Complex Conjugate Root Theorem</u>
if P(x) is a polynomial in x with <em>real coefficients</em>, and a + bi is a root of P(x) with a and b real numbers, then its complex conjugate a − bi is also a root of P(x).
The question does not specify if the quadratic equation has real coefficients, but we will assume that.
Given x=1+8i is one solution of the equation, the complex conjugate root theorem guarantees that the other solution must be x=1-8i.
I believe it’s 80 hope it helps
Answer:
x^2 + 4y^2 + 6x + 4
Step-by-step explanation:
Arranging the terms;
x ^ 2 + y^2 + 3y^2 + 4x + 2x + 2 + 2
x^2 + 4y^2 + 4x + 2x + 2 + 2
x^2 + 4y^2 + 6x + 2 + 2
x^2 + 4y^2 + 6x + 4
