Question

Use the substitution method to solve the system of equations. y=-8x and 4x-y=3

Answer 1

Answer:

x = 1/4 and y = -2

Step-by-step explanation:

$\left\{\begin{array}{ccc}y=-8x&(1)\\4x-y=3&(2)\end{array}\right\qquad\text{put (1) to (2):}\\\\4x-(-8x)=3\\4x+8x=3\\12x=3\qquad\text{divide both sides by 12}\\x=\dfrac{3}{12}\to x=\dfrac{1}{4}\\\\\text{put the value of x to (1):}\\\\y=-8\left(\dfrac{1}{4}\right)=-2$