Question

What are these two answers. Please

Answer 1

Answer:

11.   $p = 59.2^\circ$

12.   C.  $x \tan q$

Step-by-step explanation:

11.

First, find side DB.

(DB)^2 = 6^2 + 5^2

$DB = \sqrt{61}$

Now find m<p.

$\cos p = \dfrac{adj}{hyp}$

$\cos p = \dfrac{4}{\sqrt{61}}$

$p = \cos^{-1} \dfrac{4}{\sqrt{61}}$

12.

Let the height be y.

$\tan q = \dfrac{y}{x}$

$y = x \tan q$