Answer:
y =47.5.
Step-by-step explanation:
First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:
21* 6[y-2]/7-21*12 = 21*2[y-7]/3
18(y - 2) - 252 = 14(y - 7)
18y -36 - 252 = 14y - 98
18y - 14y = -98 + 36 + 252
4y = 190
y = 190/4
y = 47.5.
ABC and CBH are right angles
DBC = 90 - 37 = 53
CBJ = 90 - 31 = 59
HBD = 180 - 37 = 143
or
HBD = 31 + 53 + 59 = 143 :)
Answer:
y=3x
Step-by-step explanation:
Answer:
h'(1)=0
Step-by-step explanation:
We use the definition of the derivative of a quotient:
If , then:
Since in our case we want the derivative of at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:
which, by replacing with the given numerical values:
becomes: