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Helen [10]
3 years ago
6

In a horse race, the odds in favor of the first horse winning in an 8-horse race are 2 to 5. The odds against the second horse w

inning are 7 to 3. What is the probability that one of these horses will win
Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0

The probability that the first horse wins is 2/7. The probability that the second horse wins is 3/10. Since the events that the first horse wins and the second horse wins are shared exclusive, the probability that either the first horse or the second horse will win is :

2/7 + 3/10= 41/70

Hope this is correct.

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3(x−1) + 7=11 what is x
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Answer:

3(x-1)+7=11

3x-3-7=11

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3x=11+10

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Step-by-step explanation:

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. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?
UkoKoshka [18]

Answer:

a) 61.2, b) 38.4 and c) 4.98

Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u>As we know:</u>

<u />Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \  of\ I-pad}

5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2

a) Thus, the total width of the I-Pads are 61.2 inches.

Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \  of\ Kindles}

4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles \div Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = \frac{99.6}{20} =4.98\ inches

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

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