Hold up. Hee haw. Whoa!
Your first instinct was to multiply it out and get rid of the parentheses.
That's often a good instinct, but this time, it made things harder for you.
This is a good example of a rule you should consider:
Before you do anything to anything, sit back, relax,
LOOK at the problem, THINK about it, and plan your
strategy. Decide what the solution might look like,
and what you're going to do to the given information
in order to move towards the solution.
You might look at this particular equation and ponder:
-- If I multiplied this thing out and got rid of the parentheses, it would
have x³ in it. So there are going to be 3 solutions.
-- If either factor is zero, then the equation is true.
-- One of the factors is 6x. Setting that to zero gives one solution: x=0.
-- The other two solutions come from setting (4x² - 4) = 0 .
-- That's the difference of 2 squares, so it's (2x + 2) (2x - 2) = 0
-- The other 2 solutions come from setting each of those factors to zero.
There you are. You got this far just by thinking, without even picking up
your pencil yet.
To do this, nice it to add 3 and 5, then divide 72 by the result of sum 3 and 5. Finally multiply it by 3 and by 5 to get the result.
Lets do this
3+5=8
72:8=9 - number of rolls in 1 "unit"
9*3=27 - first group
9*5=45 - second group
Answer:
Maximum revenue = $8000
The price that will guarantee the maximum revenue is $40
Step-by-step explanation:
Given that:
Price of product = $35
Total sale of items = 225
For every dollar increase in the price, the number of items sold will decrease by 5.
The total cost of item sold = 225 ×35
The total cost of item sold = 7875
If c should be the dollar unit in price increment;
Therefore; the cost function is : ![[35+c(1)][225-5(c)]](https://tex.z-dn.net/?f=%5B35%2Bc%281%29%5D%5B225-5%28c%29%5D)
For maximum revenue;
![\dfrac{d}{dc}[[35+c(1)][225-5(c)]]=0](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdc%7D%5B%5B35%2Bc%281%29%5D%5B225-5%28c%29%5D%5D%3D0)
0+225-35× 5 -10c = 0
225 - 175 =10c
50 = 10c
c = 50/10
c = 5
Maximum revenue =
Maximum revenue = ![[35+5(1)][225-5(5)]](https://tex.z-dn.net/?f=%5B35%2B5%281%29%5D%5B225-5%285%29%5D)
Maximum revenue = (35 + 5)(225-25)
Maximum revenue = (40 )(200)
Maximum revenue = $8000
The price that will guarantee the maximum revenue is :
=(35 +c)
= 35 + 5
= $40
:)
x+x+55+x+38=180
3x+93=180
3x=87
x=29°
1 oz is 5 dollars rounded.
