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nikdorinn [45]
3 years ago
9

Speeding: On a stretch of Interstate-89, car speed is a normally distributed variable with a mean of 69.1 mph and a standard dev

iation of 3.3 mph. You are traveling at 73 mph. Approximately what percentage of cars are traveling faster than you? Enter your answer as a percentage with 1 decimal place.
Mathematics
1 answer:
Alborosie3 years ago
8 0

Answer: 11.9%

Step-by-step explanation:

Given :  On a stretch of Interstate-89, car speed is a normally distributed variable with \mu=69.1 mph and \sigma=3.3 mph.

Let x be a random variable that represents the car speed.

Since , z=\dfrac{x-\mu}{\sigma}

z-score corresponds x = 73 , z=\dfrac{73-69.1}{3.3}\approx1.18

Required probability :

\text{P-value }: P(x>73)=P(z>1.18)\\\\=1-P(z

[using z-value table.]

Hence, the approximate percentage of cars are traveling faster than you = 11.9%

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