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poizon [28]
3 years ago
13

5)List an appropriate SI base unit (with a prefix as needed ) for the following:

Physics
2 answers:
earnstyle [38]3 years ago
7 0

Explanation:

SI base units are the set of units to measure physical quantities given by international system of units.

Here, we need to write the SI base units for the following quantities.

1. The mass of a sports car  : Kilogram (kg)

2. The diameter of a pizza  : meters (m)

3. The mass of a single slice of pepperoni  : Kilogram (kg)

4. The distance from your home to school  : meters (m)

5. Your mass : Kilogram (kg)

Hence, this is the required solution.

AlexFokin [52]3 years ago
5 0
B) kg
d) cm
e)kg
g) km
h) kg
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When light of wavelength 240 nm falls on a cobalt surface, electrons having a maximum kinetic energy of 0.17 eV are emitted. Fin
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Answer:

(a) 5.04 eV (B) 248.14 nm (c) 1.21\times 10^{15}Hz

Explanation:

We have given Wavelength of the light  \lambda = 240 nm

According to plank's rule ,energy of light

E = h\nu = \frac{hc}{}\lambda

E = h\nu = \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{ 240\times 10^{-9} m\times 1.6\times 10^{-19}J/eV}= 5.21 eV

Maximum KE of emitted electron i= 0.17 eV

Part( A) Using Einstien's equation

E = KE_{max}+\Phi _{0}, here \Phi _0 is work function.

\Phi _{0}=E - KE_{max}= 5.21 eV-0.17 eV = 5.04 eV

Part( B) We have to find cutoff wavelength

\Phi _{0} = \frac{hc}{\lambda_{cuttoff}}

\lambda_{cuttoff}= \frac{hc}{\Phi _{0} }

\lambda_{cuttoff}= \frac{6.67\times 10^{-34} J.s\times 3\times 10^{8}m/s}{5.04 eV\times 1.6\times 10^{-19}J/eV }=248.14 nm

Part (C) In this part we have to find the cutoff frequency

\nu = \frac{c}{\lambda_{cuttoff}}= \frac{3\times 10^{8}m/s}{248.14 \times 10^{-19} m }= 1.21\times 10^{15} Hz

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