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wolverine [178]

3 years ago

13

When I drop a bouncy ball it bounces back up to me. What force causes it to bounce?

2 answers:

Darya [45]3 years ago

6 0

I do not think that there is a "force" that causes it to bounce. it's the rubber (or whatever material) makes up the ball.

SVEN [57.7K]3 years ago

6 0

Gravity pulls the ball down to the centre of the Earth but the ground resists the ball in the opposite direction. If there was no resistance the ball would phase through the ground. This is Newton's Second Law. However since the ball is made of rubber (just an assumption), the force of the floor resisting the ball is higher than the force of gravity, hence the ball then flies back up.

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The mass of a moving object increases, but its speed stays the same. What happens to the kinetic energy of the object as a resul

Ronch [10]

We Know, K.E. = 1/2 × m × v²
From the expression, we can conclude that Kinetic energy is directly proportional to mass. So, as mass will increase, Kinetic energy will also increase.

In short, Your Correct answer would be Option B

Hope this helps!

8 0

3 years ago

Read 2 more answers

A 9-μC positive point charge is located at the origin and a 6 μC positive point charge is located at x = 0.00 m, y = 1.0 m. Find

sukhopar [10]

Answer:

The coordinates of the point is (0,0.55).

Explanation:

Given that,

First charge $q_{1}=9\times10^{-6}\ C$ at origin

Second charge $q_{2}=6\times10^{-6}\ C$

Second charge at point P = (0,1)

We assume that,

The net electric field between the charges is zero at mid point.

Using formula of electric field

$E=\dfrac{kq}{r^2}$

$0=\dfrac{k\times9\times10^{-6}}{d^2}+\dfrac{k\times6\times10^{-6}}{(1-d)^2}$

$\dfrac{(1-d)}{d}=\sqrt{\dfrac{6}{9}}$

$\dfrac{1}{d}=\dfrac{\sqrt{6}}{3}+1$

$\dfrac{1}{d}=1.82$

$d=\dfrac{1}{1.82}$

$d=0.55\ m$

Hence, The coordinates of the point is (0,0.55).

3 0

3 years ago

Why does a solid change to liquid when heat is added

marissa [1.9K]

heat excites molecules at their "lattice" sites. Enough to break the lattice bonds set the molecules free of each other and ... melt.

8 0

3 years ago

A very long straight wire has charge per unit length 1.56×10−10 C/m .

77julia77 [94]

Answer:

The magnitude of the electric field equal to 2.40 N/C at 1.1537m from the wire.

Explanation:

using Guass law,

(guessing that a cylinder of radius r and length L around wire such that wire is at centre )

E. A = qin / e0

E ( 2πr L ) = (1.56 x $10^{-10}$ x L) / (8.85 x $10^{-12}$ )

E = (1.56 x $10^{-10}$ ) / (2πr x 8.85 x $10^{-12}$ )

so 2.40 = (1.54 x $10^{-10}$ ) / (2πr x 8.85 x $10^{-12}$ )

2.40 (6.284r) = 0.174 x 10²

15.0816r = 17.4

r = 1.1537m

6 0

3 years ago

By applying a force of one Newton, one can hold a body of mass _

SVEN [57.7K]

Answer:

By applying a force of one Newton, one can hold a body of mass of 102 gram.

Explanation:

Force is the pull or push of an object. It can be mathematically measured as, F= m* g.

where, F= force in newton

m= mass in kg

g= acceleration due to gravity ( $meter/second^{2}$ )

For 1 newton force,

F= m* 9.8

or, m= $\frac{1}{9.8}$ = 0.102 kg

or, m= 102 gram.

Hence, 102 gram mass can be hold by one Newton force.

3 0

3 years ago