The quantity of matter in a body regardless of its volume or of any forces acting on it.
Answer:
16km
Explanation:
First change the minutes into hours then multiply by the distance.
(8÷60)×120=16km
Answer:
Mass of the aluminium chunk = 278.51 g
Explanation:
For an isolated system as given the energy lost and gains in the system will be zero therefore sum of all transfer of energy will be zero,as the temperature will also remain same
A specific heat formula is given as
Energy Change = Mass of liquid x Specific Heat Capacity x Change in temperature
Q = m×c×ΔT
Heat gain by aluminium + heat lost by copper = 0 (1)
For Aluminium:
Q = 
Q = m x 17.94 joule
For Copper:

Q= 4996.53 Joule
from eq 1
m x 17.94 = 4996.53

Mass of the aluminium chunk = 278.51 g
Answer:

Explanation:
The problem tell us that the temperature as function of time in downtown mathville is given by:

The average temperature over a given interval can be calculated as:

Where:

So, the initial temperature in this case, would be the temperature at noon, and the final temperature would be the temperature at midnight:
Therefore:


Hence, the average temperature between noon and midnight is:

Answer:
6.6 atm
Explanation:
Using the general gas law
P₁V₁/T₁ = P₂V₂/T₂
Let P₂ be the new pressure
So, P₂ = P₁V₁T₂/V₂T₁
Since V₂ = 2V₁ , P₁ = 12 atm and T₁ = 273 + t where t = temperature in Celsius
T₂ = 273 + 2t (since its Celsius temperature doubles).
Substituting these values into the equation for P₂, we have
P₂ = P₁V₁(273 + 2t)/2V₁(273 + t)
P₂ = 12(273 + 2t)/[2(273 + t)]
P₂ = 6(273 + 2t)/(273 + t)]
assume t = 30 °C on a comfortable spring day
P₂ = 6(273 + 2(30))/(273 + 30)]
P₂ = 6(273 + 60))/(273 + 30)]
P₂ = 6(333))/(303)]
P₂ = 6.6 atm