1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Musya8 [376]
3 years ago
6

A spring scale hung from the ceiling stretches by 6.1 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl

aced with a 2.5 kg mass.
Part A What is the stretch of the spring? A spring scale hung from the ceiling stretches by 6.1 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and replaced with a 2.5 kg mass.
Part A What is the stretch of the spring?
Physics
1 answer:
Hunter-Best [27]3 years ago
6 0

The ideal spring equation is

                               Stretch  =  K  times  Force  .

This says that the stretch is directly proportional to the force.
In simple English, that means that if you double the force, then
you double the stretch, and if you multiply the force by  π  or
any other number, you multiply the stretch by the same number.

So you can always write a proportion for a spring:

                 Stretch₁ / Force₁  =  Stretch₂ / Force₂ .

Part A:

In Part-A of this question, the force is increased to  (2.5 / 2.0) =  1.25 times .

So the stretch is also increased to  1.25 times .

                 (1.25) x (6.1 cm)  =  7.625 cm  .
You might be interested in
Which of the following best expresses the definition of mass?
sergey [27]
The quantity of matter in a body regardless of its volume or of any forces acting on it.
4 0
3 years ago
A sailfish swims 120 km/hr. How far will it travel in 8.0 minutes?
Rasek [7]

Answer:

16km

Explanation:

First change the minutes into hours then multiply by the distance.

(8÷60)×120=16km

5 0
3 years ago
A student drops two metallic objects into a 120-g steel container holding 150 g of water at 25°C. One object is a 206-g cube of
spayn [35]

Answer:

Mass of the aluminium chunk = 278.51 g

Explanation:

For an isolated system as given the energy lost and gains in the system will be zero therefore sum of all transfer of energy will be zero,as the temperature will also remain same

A specific heat formula is given as                  

Energy Change = Mass of liquid x Specific Heat Capacity x Change in temperature

                                       Q =  m×c×ΔT

                        Heat gain by aluminium + heat lost by copper  = 0    (1)

For Aluminium:

      Q = m\times0.897\frac{J}{g.k}\times(25-5)

      Q = m x 17.94 joule

For Copper:

Q= 206g\times0.385\frac{J}{g.k} \times(88-25)

       Q= 4996.53 Joule

from eq 1

     m x 17.94 = 4996.53

     mass of aluminium = \frac{4996.53}{17.94} g

    Mass of the aluminium chunk = 278.51 g

                         

3 0
3 years ago
The temperature and time t given in hours from 0 to 24 after midnight in downtown mathville is given by t=10-5 sin(pi/12 t) degr
Dvinal [7]

Answer:

T_A_v_g=9.918192559$^{\circ}C

Explanation:

The problem tell us that the temperature as function of time in downtown mathville is given by:

T(t)=10-5*sin(\frac{\pi}{12t})

The average temperature over a given interval can be calculated as:

T_a_v_g=\frac{T_o+T_f}{2}

Where:

T_o=Initial\hspace{3}temperature\\T_f=Final\hspace{3}temperature

So, the initial temperature in this case, would be the temperature at noon, and the final temperature would be the temperature at midnight:

Therefore:

T_o=T(12)=10-5*sin(\frac{\pi}{12*12}) =9.890925575$^{\circ}C

T_f=T(24)=10-5*sin(\frac{\pi}{12*24}) =9.945459543$^{\circ}C

Hence, the average temperature between noon and midnight is:

T_A_v_g=\frac{9.890925575+9.945459543}{2}=9.918192559$^{\circ}C

3 0
3 years ago
consider a sample of gas in a container on a comfortable spring day. the Celsius temperature suddenly doubles, and you transfer
Tasya [4]

Answer:

6.6 atm

Explanation:

Using the general gas law

P₁V₁/T₁ = P₂V₂/T₂

Let P₂ be the new pressure

So, P₂ = P₁V₁T₂/V₂T₁

Since V₂ = 2V₁ , P₁ = 12 atm and T₁ = 273 + t where t = temperature in Celsius

T₂ = 273 + 2t (since its Celsius temperature doubles).

Substituting these values into the equation for P₂, we have

P₂ = P₁V₁(273 + 2t)/2V₁(273 + t)

P₂ = 12(273 + 2t)/[2(273 + t)]

P₂ = 6(273 + 2t)/(273 + t)]

assume t = 30 °C on a comfortable spring day

P₂ = 6(273 + 2(30))/(273 + 30)]

P₂ = 6(273 + 60))/(273 + 30)]

P₂ = 6(333))/(303)]

P₂ = 6.6 atm

7 0
3 years ago
Other questions:
  • An ideal gas trapped inside a thermally isolated cylinder expands slowly by pushing back against a piston. The temperature of th
    11·1 answer
  • A camera lens focuses on an object 75.0 cm from the lensThe image forms 3.50 cm behind the lens. What is the magnification of th
    10·1 answer
  • If your kinetic energy is different from your work input (either greater or less) throuroughly explain what caused this discrepe
    8·1 answer
  • PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
    14·1 answer
  • The formation of volcanos and mountain ranges can be explained by the theroy of _____
    11·1 answer
  • A LOT OF POINTS! In your own words, compare and contrast transverse and longitudinal waves. Be sure to include at least one simi
    14·1 answer
  • How to keep my family safe during a hurricane?
    9·1 answer
  • What conditions must be met in order for work to be done?
    9·1 answer
  • The figure shows an uncharged conducting cubic shell and a positive point charge Q outside the shell. There are two lettered poi
    13·1 answer
  • Place the following types of electromagnetic radiation in order from LOWEST energy
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!