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Musya8 [376]
3 years ago
6

A spring scale hung from the ceiling stretches by 6.1 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl

aced with a 2.5 kg mass.
Part A What is the stretch of the spring? A spring scale hung from the ceiling stretches by 6.1 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and replaced with a 2.5 kg mass.
Part A What is the stretch of the spring?
Physics
1 answer:
Hunter-Best [27]3 years ago
6 0

The ideal spring equation is

                               Stretch  =  K  times  Force  .

This says that the stretch is directly proportional to the force.
In simple English, that means that if you double the force, then
you double the stretch, and if you multiply the force by  π  or
any other number, you multiply the stretch by the same number.

So you can always write a proportion for a spring:

                 Stretch₁ / Force₁  =  Stretch₂ / Force₂ .

Part A:

In Part-A of this question, the force is increased to  (2.5 / 2.0) =  1.25 times .

So the stretch is also increased to  1.25 times .

                 (1.25) x (6.1 cm)  =  7.625 cm  .
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Explorers on a small airless planet used a spring gun to launch a ball bearing vertically upward from the surface at a launch ve
Oksana_A [137]

Answer:

gs = 0.6 m/s^2

Explanation:

Given data:

velocity = 12 m/s

height s = 12t -(1/2) g_s t^2

Given velocity is the derivatives of  height

v(t) = \frac{d}{dt} s(t)

      = \frac{d}{dt}(12t -\frac{1}{2} g_s t^2)

      = 12 - g_s t

when velocity tend to 0 , maximum height is reached

v(t) = 12 - g_s t

0 = 12 - g_s t

g_s = \frac{12}{t}

at t = 20 sec ball reached the max height, so

g_s = \frac{12}{20} = 0.6 m/s^2

5 0
2 years ago
Four equal masses M are spaced at equal intervals (each of length d) along a horizontal, straight rod whose mass can be ignored.
Mars2501 [29]

Answer:

a) 14Md^{2}

Explanation:

a)The inertia of a particle moving in a circular axis is given by,

I=Mr^{2} \\

I = Moment of inertia

M = mass of the particle

r = perpendicular distance from axis of rotation.

And by adding moment of inertia of each particle we can come to the moment of inertia of the system.

I = M(0d)^{2}+Md^{2} +M(2d)^{2}+M(3d)^{2}

 = 14Md^{2}

b) Your question is incomplete but I'll write how to find the minimum force required  to give a system given angular acceleration.

Minimum force is found when applied from the furthest point to the axis of rotation in the system.

, by τ = Fr, whereτ = torque , F = Force ,  = perpendicular distance from axis of rotation.

For minimum force r = 3d

And also τ = Iα where I = Moment of inertia and α = angular acceleration

By combining the two equations you get minimum force as,

F = Iα/r

F' = 14Md^{2}α/3d

  = 14Mαd/3

7 0
3 years ago
If the angle of incidence is 30°, degrees what is the angle of reflection? ​
algol13

Answer:

Angle of reflection = 30°

Explanation:

One of the laws of reflection is that the angle of incidence is equal to the angle of reflection.

The angle at which the light strikes the mirror is called the angle of incidence while the angle at which the light gets reflected back is called angle of reflection.

In this case, the angle of incidence is 30 degrees. So, we can say that the angle of reflection is also equal to 30 degrees.

3 0
3 years ago
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