We have that the time in seconds, minutes, and hours is
From the Question we are told that
Velocity
Distance
Generally the equation for the Time is mathematically given as
Therefore
And
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A spring scale hung from the ceiling stretches by 6.1 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl
1 answer:
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Answer:
Smallest drop: Water
Largest drop: Dirt
Explanation:
The heat needed to change the temperature of a sample is:
(1)
with Q the heat (added(+) or removed(-)), c specific heat, m the mass and the change in temperature of the sample. So, if we solve (1) for
Sample A:
Sample B:
Sample C:
Note that the numbers 16744, 5400, 9450 are in the denominator of the expression that gives the drop on temperature. so, if Q is the same for the three samples the smallest denominator gives the largest drop and vice versa.
So, the smallest drop is Sample A and the largest is Sample C.
(Important: The minus sign of implies the temperature is dropping)
Answer:
(a) v = 5.42m/s
(b) vo = 4.64m/s
(c) a = 2874.28m/s^2
(d) Δy = 5.11*10^-3m
Explanation:
(a) The velocity of the ball before it hits the floor is given by:
(1)
g: gravitational acceleration = 9.8m/s^2
h: height where the ball falls down = 1.50m
The speed of the ball is 5.42m/s
(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.
You use the following formula:
(2)
vo: velocity of the ball where it starts its motion upward
You solve for vo and replace the values of the parameters:
The velocity of the ball is 4.64m/s
(c) The acceleration is given by:
The acceleration of the ball is 2874.28/s^2
(d) The compression of the ball is:
THe compression of the ball when it strikes the floor is 5.11*10^-3m
Answer:
The bulk modulus of the liquid is 1.534 x 10¹⁰ N/m²
Explanation:
Given;
density of the liquid, ρ = 1500 kg/m³
frequency of the wave, F = 410 Hz
wavelength of the sound, λ = 7.80 m
The speed of the wave is calculated as;
v = Fλ
v = 410 x 7.8
v = 3,198 m/s
The bulk modulus of the liquid is calculated as;
Therefore, the bulk modulus of the liquid is 1.534 x 10¹⁰ N/m²