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Oliga [24]
3 years ago
7

Two arrows are shot vertically upward. the second arrow is shot after the first one, but while the first is still on its way up.

the initial speeds are such that both arrows reach their maximum heights at the same instant, although these heights are different. suppose that the initial speed of the first arrow is 31.8 m/s and that the second arrow is fired 1.82 s after the first. determine the initial speed of the second arrow.
Physics
1 answer:
Neko [114]3 years ago
7 0
<span>Now that you know the time to reach its maximum height, you have enough information to find out the initial velocity of the second arrow. Here's what you know about it: its final velocity is 0 m/s (at the maximum height), its time to reach that is 2.8 seconds, but wait! it was fired 1.05 seconds later, so take off 1.05 seconds so that its time is 1.75 seconds, and of course gravity is still the same at -9.8 m/s^2. Plug those numbers into the kinematic equation (Vf=Vi+a*t, remember?) for 0=Vi+-9.8*1.75 and solve for Vi to get....... 17.15 m/s</span>
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How can you tell if something has a lot of kinetic energy? How can you tell if something only has a little bit of kinetic energy
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3 years ago
During a very quick stop, a car decelerates at 7.6 m/s2. Assume the forward motion of the car corresponds to a positive directio
Mashcka [7]

Answer:

24.57 revolutions

Explanation:

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(b) We can use the following equation of motion to find out the angle traveled by the wheel before coming to rest:

\omega^2 - \omega_0^2 = 2\alpha\Delta \theta

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8 0
3 years ago
Somebody can tell me what answers it is?
sergij07 [2.7K]

Answer:

D

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6 0
3 years ago
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Answer:

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Explanation:

Given data

focal length = 3.06 cm

distance = 10.4 m = 1040 cm

to find out

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solution

we apply here lens formula that is

1/f = 1/p + 1/q

here f = 3.06 and p = 1040 so we find q

1/f = 1/p + 1/q

1/3.06 = 1/1040 + 1/q

1/ q =  0.3258

q = 3.0690 cm

so film is at distance of 3.07 cm from lens

6 0
3 years ago
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