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prohojiy [21]
2 years ago
11

A box rests on top of a flat bed truck. the box has a mass of m = 18 kg. the coefficient of static friction between the box and

truck is μs = 0.86 and the coefficient of kinetic friction between the box and truck is μk = 0.69. 1) the truck accelerates from rest to vf = 16 m/s in t = 16 s (which is slow enough that the box will not slide). what is the acceleration of the box?
Physics
1 answer:
konstantin123 [22]2 years ago
5 0
For this case, the first thing you should do is write the kinematic motion equation of the block.
 We have then:
 vf = vo + a * t
 Where,
 vf: Final speed.
 vo: Initial speed.
 a: acceleration.
 t: time.
 Substituting the values:
 (16) = (0) + a * (16)
 Clearing the acceleration:
 a = 16/16 = 1m / s ^ 2
 Note: the other data for this case are not used in this problem.
 answer:
 The acceleration of the box is 1m / s ^ 2
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Suppose all of the apples have a mass of 0.10 kg and one of the apples in the bowl (C) is 1.0 meter off the ground. If the apple
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un motor electric efectueaza un lucru mecanic de 864 j in 0.5 min.tensiunea la bornele sale este de 12v si este parcurs de un cu
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Answer:

96%

Explanation:

To find the values of the motor efficiency you use the following formula:

E=\frac{P_o}{P_i}100

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By replacing this values you obtain:

E=\frac{28.8W}{30W}*100=96\%

hence, the motor efficiency is about 96%

traslation:

Pentru a găsi valorile eficienței motorului, utilizați următoarea formulă:

P_o: putere de ieșire = 864J / 0.5min = 864J / 30s = 28.8W

P_i: putere de intrare = I * V = (3A) (12V) = 36W

Înlocuind aceste valori obțineți:

prin urmare, eficiența motorului este de aproximativ 96%

3 0
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