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prohojiy [21]
2 years ago
11

A box rests on top of a flat bed truck. the box has a mass of m = 18 kg. the coefficient of static friction between the box and

truck is μs = 0.86 and the coefficient of kinetic friction between the box and truck is μk = 0.69. 1) the truck accelerates from rest to vf = 16 m/s in t = 16 s (which is slow enough that the box will not slide). what is the acceleration of the box?
Physics
1 answer:
konstantin123 [22]2 years ago
5 0
For this case, the first thing you should do is write the kinematic motion equation of the block.
 We have then:
 vf = vo + a * t
 Where,
 vf: Final speed.
 vo: Initial speed.
 a: acceleration.
 t: time.
 Substituting the values:
 (16) = (0) + a * (16)
 Clearing the acceleration:
 a = 16/16 = 1m / s ^ 2
 Note: the other data for this case are not used in this problem.
 answer:
 The acceleration of the box is 1m / s ^ 2
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Answer:

3.75*10^{-13}  electrons

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2 years ago
What is the fundamental frequency (in Hz) of a 0.632 m long tube, open at both ends, on a day when the speed of sound is 344 m/s
Greeley [361]

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