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nadezda [96]
3 years ago
9

A person uses their hand to lift a 0.05-kg guniea pig from the ground at a constand speed.What is the force applied by the perso

n on the guinea pig? What is the net force on the guinea pig?
Physics
1 answer:
Ostrovityanka [42]3 years ago
3 0
The animal's weight is

                         (mass) x (gravity)

                 =      (0.05 kg) x (9.8 m/s²)  =  0.49 newton.

That's the minimum force you can use to pick it up.

That's the force applied by the person to pick up the pig
at a nice gentle constant speed.

Then the net force on the pig is zero.  The upward and downward
forces add up to zero, and that's why the animal is moving at a
constant speed, and not accelerating up or down.
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5. George walks to a friend's house. He walks 750 meters North, then realizes he walked too far.
dedylja [7]

Answer:

Average speed: approximately 76.9\; {\rm m\cdot s^{-1}}.

Average velocity: approximately 38.5\; {\rm m \cdot s^{-1}} (to the north.)

Explanation:

Consider an object that travelled along a certain path. Distance travelled would be equal to the length of the entire path.

In contrast, the magnitude of displacement is equal to distance between where the object started and where it stopped.

In this question, the path George took required him to travel 750\; {\rm m} + 250\; {\rm m} = 1000\; {\rm m} in total. Hence, the distance George travelled would be 1000\; {\rm m}. However, since George stopped at a point (750\; {\rm m} - 250\; {\rm m}) = 500\; {\rm m} to the north of where he started, his displacement would be only 500\; {\rm m} to the north.

Divide total distance by total time to find the average speed.

Divide total displacement by total time to find average velocity.

The total time of travel in this question is 13\; {\rm s}.. Therefore:

\begin{aligned}\text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &= \frac{1000\; {\rm m}}{13\; {\rm s}} \\ &\approx 76.9\; {\rm m\cdot s^{-1}}\end{aligned}.

\begin{aligned}\text{average velocity} &= \frac{\text{total displacement}}{\text{total time}} \\ &= \frac{500\; {\rm m}}{13\; {\rm s}} && \genfrac{}{}{0px}{}{(\text{to the north})}{}\\ &\approx 38.5\; {\rm m\cdot s^{-1}} && (\text{to the north})\end{aligned}.

3 0
2 years ago
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Blababa [14]

Please find attached photograph for your answer. Hope it helps. Please do comment.

7 0
3 years ago
A voltmeter is a device that measures _____.
olga55 [171]
A voltmeter<span> its </span>instrument<span> used for </span>measuring<span> electrical potential difference between two points in an electric circuit. </span>An ammeter<span> is a </span>measuring device<span> used to</span>measure<span> the electric current in a circuit.

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5 0
3 years ago
Read 2 more answers
Jack travelled 360 km at an average speed of 80 km/h. Elaine
diamong [38]

Answer:

Average speed of Elain = 60 km/h

Explanation:

Total Distance covered by Jack = 360km

Average Speed of Jack = 80 km/h

Time taken by Jack to complete his journey = Distance / Average speed = 360 km / 80 km/h

Time taken by Jack to complete his journey = 4.5 hours

As it is given the both Jack and Elain travelled the same amount of distance:

Total distance travelled by Elain = 360 km

It is given that Elain took 1.5 hourse more than Jack to cover the distance, so Time taken by Elain to cover the distance is = 4.5 hours + 1.5 hours = 6 hours

Average speed of Elain = Distance/ time = 360 km / 6 hours

Average speed of Elain = 60 km/h

3 0
3 years ago
What Is the volume of the rectangular prism of 6cm 9cm and 5cm
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Volume is length  times width times height, so 6 times 9 times 5 is 270 centimeters.
8 0
3 years ago
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