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nadezda [96]
3 years ago
9

A person uses their hand to lift a 0.05-kg guniea pig from the ground at a constand speed.What is the force applied by the perso

n on the guinea pig? What is the net force on the guinea pig?
Physics
1 answer:
Ostrovityanka [42]3 years ago
3 0
The animal's weight is

                         (mass) x (gravity)

                 =      (0.05 kg) x (9.8 m/s²)  =  0.49 newton.

That's the minimum force you can use to pick it up.

That's the force applied by the person to pick up the pig
at a nice gentle constant speed.

Then the net force on the pig is zero.  The upward and downward
forces add up to zero, and that's why the animal is moving at a
constant speed, and not accelerating up or down.
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Answer:

La motocicleta recorre 25 metros en 1 segundo si circula a una velocidad de 90 km/h

Explanation:

La velocidad es una magnitud que expresa el desplazamiento que realiza un objeto en una unidad determinada de tiempo, esto es, relaciona el cambio de posición (o desplazamiento) con el tiempo.

Siendo la velocidad es el espacio recorrido en un período de tiempo determinado, entonces 90 km/h indica que en 1 hora la motocicleta recorre 90 km. Entonces, siendo 1 h= 3600 segundos (1 h=60 minutos y 1 minuto=60 segundos) podes aplicar la siguiente regla de tres: si en 3600 segundos (1 hora) la motocicleta recorre 90 km, entonces en 1 segundo ¿cuánta distancia recorrerá?

distancia=\frac{1 segundo*90 km}{3600 segundos}

distancia= 0.025 km

Por otro lado, aplicas la siguiente regla de tres: si 1 km es igual a 1,000 metros, ¿0.025 km cuántos metros son?

distancia=\frac{0.025 km*1,000 metros}{1 km}

distancia= 25 metros

<u><em>La motocicleta recorre 25 metros en 1 segundo si circula a una velocidad de 90 km/h</em></u>

6 0
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Here is your answer:

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Your answer is B.

If you need anymore help feel free to ask me!

Hope this helps.
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