Answer:
It is given that power = 5000 W for 120 V and resistance is
per 1000 ft of wire. The wire is 750 ft away from 120 V source. We need find the voltage delivered to this load.
![Power, P=Voltage(E)\times Current(I)](https://tex.z-dn.net/?f=Power%2C%20P%3DVoltage%28E%29%5Ctimes%20Current%28I%29)
![\Rightarrow I=\frac{P}{E}=\frac{5000W}{120V}=41.67 A](https://tex.z-dn.net/?f=%5CRightarrow%20I%3D%5Cfrac%7BP%7D%7BE%7D%3D%5Cfrac%7B5000W%7D%7B120V%7D%3D41.67%20A)
Resistance of 750 ft wire, =![R=\frac{1.24\Omega}{1000 ft}\times750 ft=0.93\Omega](https://tex.z-dn.net/?f=R%3D%5Cfrac%7B1.24%5COmega%7D%7B1000%20ft%7D%5Ctimes750%20ft%3D0.93%5COmega)
Using Ohm's Law:
Voltage delivered to the load, ![V=IR](https://tex.z-dn.net/?f=V%3DIR)
![\Rightarrow V=41.67A\times0.93\Omega=38.75 V](https://tex.z-dn.net/?f=%5CRightarrow%20V%3D41.67A%5Ctimes0.93%5COmega%3D38.75%20V)
<span>342 m/s This should be correct, but please tell me if it is incorrect!</span>
Answer:
a= (-g) from the moment the ball is thrown, until it stops in the air.
a = (0) when the ball stops in the air.
a = (g) since the ball starts to fall.
Explanation:
The acceleration is <em>(-g)</em> <em>from the moment the ball is thrown, until it stops in the air</em> because the movement goes in the opposite direction to the force of gravity. In the instant <em>when the ball stops in the air the acceleration is </em><em>(0)</em> because it temporarily stops moving. Then, <em>since the ball starts to fall, the acceleration is </em><em>(g)</em><em> </em>because the movement goes in the same direction of the force of gravity
Answer:
Explanation:
log10 function is required to convert dB into intensity of a sound. Both are measures of loudness of a sound and the relationship can be expressed as follows:
dB = 10 log10(I/Io), where Io is 10^-12 W/m^2
Substituting, 82 = 10 log10(I/10^-12)
I = 0.0001585 W/m^2
or 1.58*10^-4 W/m^2