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GarryVolchara [31]
4 years ago
15

Water molecules are polar because the:

Chemistry
2 answers:
Alinara [238K]4 years ago
5 0

Answer: B) water molecule has a bent shape.

Explanation: Water is a covalent compound formed by sharing of electrons between hydrogen and oxygen. Oxygen is more electronegative as compared to hydrogen and thus attracts the electron pairs towards itself and thus is polar.

Hybridization and shape of H_2O

:{\text{Number of electrons}} =\frac{1}{2}[V+N-C+A]

where, V = number of valence electrons present in central atom i.e. oxygen = 6

N = number of monovalent atoms bonded to central atom=32

C = charge of cation = 0

A = charge of anion = 0

{\text{Number of electrons}} =\frac{1}{2}[6+2-0+0]=4

The number of electrons is 4 that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral.

But as there are two atoms around the central oxygen, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent.

Arada [10]4 years ago
3 0

<u>Answer;</u>

B) water molecule has a bent shape.

<u>Explanation;</u>

  • Water molecules are polar molecules because of their shape. Water molecules have one side that is positively charged due to hydrogen atom which is partially positive and the other side which is negatively charged, due to the oxygen atom.
  • When two molecules get close to each other the polar forces of attraction brings them close to each other. Oxygen bonds with several hydrogen atoms in the other water molecules resulting to hydrogen bonds.
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The general formula of the hydrate is Caa Seb Oc. nH2O. Based on the given information, the weight of the hydrated compound is 256.3 grams, the weight of the anhydrous compound is 214.2 grams.  

Therefore, the weight of water evaporated is 256.3 g - 214.2 g = 42.1 grams

The molecular weight of water is 18 gram per mole. So, the number of moles of water will be,  

Moles of water = weight of water/molecular weight

= 42.1 grams / 18 = 2.3

The given composition of calcium is 21.90 %. So, the concentration of calcium in anhydrous compound is,  

= 214.2 * 0.2190 = 46.91 grams

The given composition of Se is 43.14 %. So, the concentration of selenium in anhydrous compound is,

= 214.2 * 0.4314 = 92.40 grams

The given composition of oxygen is 34.97%, So, the concentration of oxygen in anhydrous compound is,  

= 214.2 * 0.3497 = 74.91 grams

The molecular weight of Ca is 40.078, the obtained concentration is 46.91 grams, stoichiometry will be, 46.91/40.078 = 1.17

The molecular weight of Se is 78.96, the obtained concentration is 92.40, stoichiometry will be,  

92.40/78.96 = 1.17

The molecular weight of Oxygen is 15.999, the concentration obtained is 74.91, the stoichiometry will be,  

74.91/15.999 = 4.68.  

Thus, the formula becomes, Ca1.17. Se1.1e O4.68. 2.3H2O, the closest actual component is CaSeO4.2H2O

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