1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rusak2 [61]
3 years ago
13

Suizi bought 5 packages of M&M and each package contained 18 candy pieces. She opened the frist package and counted 4 green

pieces. She then counted 3 green in the second package
Mathematics
1 answer:
masha68 [24]3 years ago
5 0
<h3>There are fewer than 14 green pieces in all 5 packages. </h3>

Step-by-step explanation:

Here, the given question is incomplete.

Suzi bought 5 packages of M&M's, and each package contained 18 candy pieces. She opened the first package and counted 4 green pieces. She then counted 3 green pieces in the second package. Which statement about the candy pieces in the remaining packages is best supported by this information?

A. There are fewer than 14 green pieces in all 5 packages.

B. There are between 15 and 20 green pieces in all 5 packages.

C. There are at least 25 green pieces but no more than 50 in all 5 packages. D. There are more than 50 green pieces in all 5 packages.

Now, here given:

The number of packages of M & M purchased  = 5 packets

The number of candies in each packet = 18

The number of green candies in first pack  = 4

The number of green candies in second pack  = 3

Now as we can see the number of green candies in <u>decreasing by 1</u><u> </u>in number as we open more packets.

So, according to this pattern:

The number of green candies in third pack  = 2

The number of green candies in fourth pack  = 1

And the fifth pack will have NO green candies.

So, the total number of green candies in all 5 packets combined  

=  4  + 3+ 2 + 1 + 0

=  10 green candies

⇒  There are fewer than 14 green pieces in all 5 packages.

You might be interested in
At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic
finlep [7]

Answer:

a) We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) P(C=0) = 0.05

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C    0        1        2         3       4       5        6       7        8      

P  0.05   0.14   0.34   0.24  0.11  0.07  0.02  0.02  0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

P(C=0) = 0.05

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

5 0
3 years ago
4x+2y+9+3y+12x+20=<br> How do you solve this expression?
balu736 [363]

Answer:

5y+16x+29

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Perimeter of a rectangle with these dimentions w--12 l--10
GuDViN [60]
Perimeter = 2w + 2l = 2(12) + 2(10) = 44 
4 0
3 years ago
Solve.<br> 92.5÷105 brainliest
Karo-lina-s [1.5K]

Answer:

\frac{37}{42}

Step-by-step explanation:

Given :

\frac{92.5}{105}

Multiply numerator and denominator by 2 :

\frac{92.5}{105} \times\frac{2}{2}

\frac{185}{210}          [Divide both sides by 5 as it is a common factor]

\frac{185}{210} \div \frac{5}{5}

\frac{37}{42}

6 0
2 years ago
Read 2 more answers
Calculate the second moment of area of a 4-in-diameter shaft about the x-x and yy axes, as shown.
Keith_Richards [23]
Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.

The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.

6 0
3 years ago
Other questions:
  • Charlie uses 2 2/3 ounces of garlic to help make a jar of spaghetti sauce. Yesterday, he used 3 1/6 ounces of garlic. How many j
    12·1 answer
  • PLEASE ANSWER U NEED HELP!! determine which numbers The equations need to be multiplied by to form opposite terms of the y varia
    13·2 answers
  • The length of the arc intercepted by a congruent central angle is proportional to the _______ in similar circles.
    12·1 answer
  • Evaluate the following expression.
    12·1 answer
  • Analyze the diagram below and complete the instructions that follow. find tan c
    14·1 answer
  • Having trouble with this one can someone teach me how to find the slope in this question. Try to help me learn it aswell. Its in
    11·1 answer
  • Which of the following lines intersects the line y = 2x + 1 at the point (1,3)?
    15·1 answer
  • OK people stop putting your questions in the awnser box because you are just using poibts that can go to other people who actual
    12·1 answer
  • HELP me please Show work tooo
    12·2 answers
  • Can i get some help on this 3 ½x = -70
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!