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rusak2 [61]
3 years ago
13

Suizi bought 5 packages of M&M and each package contained 18 candy pieces. She opened the frist package and counted 4 green

pieces. She then counted 3 green in the second package
Mathematics
1 answer:
masha68 [24]3 years ago
5 0
<h3>There are fewer than 14 green pieces in all 5 packages. </h3>

Step-by-step explanation:

Here, the given question is incomplete.

Suzi bought 5 packages of M&M's, and each package contained 18 candy pieces. She opened the first package and counted 4 green pieces. She then counted 3 green pieces in the second package. Which statement about the candy pieces in the remaining packages is best supported by this information?

A. There are fewer than 14 green pieces in all 5 packages.

B. There are between 15 and 20 green pieces in all 5 packages.

C. There are at least 25 green pieces but no more than 50 in all 5 packages. D. There are more than 50 green pieces in all 5 packages.

Now, here given:

The number of packages of M & M purchased  = 5 packets

The number of candies in each packet = 18

The number of green candies in first pack  = 4

The number of green candies in second pack  = 3

Now as we can see the number of green candies in <u>decreasing by 1</u><u> </u>in number as we open more packets.

So, according to this pattern:

The number of green candies in third pack  = 2

The number of green candies in fourth pack  = 1

And the fifth pack will have NO green candies.

So, the total number of green candies in all 5 packets combined  

=  4  + 3+ 2 + 1 + 0

=  10 green candies

⇒  There are fewer than 14 green pieces in all 5 packages.

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Julia has determined that CE is perpendicular bisector of AB. The next step of a valid proof would be: <em>B. AC = BC based on the </em><em>perpendicular bisector theorem</em>.

<h3>What is the Perpendicular Bisector Theorem?</h3>

The perpendicular bisector theorem states that if a point is located on a segment (perpendicular bisector) that divides another segment into two halves, then it is equidistant from the two endpoints of the segment that is divided.

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Learn more about the perpendicular bisector theorem on:

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