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erma4kov [3.2K]
3 years ago
10

On his math test, Balavan wrote that a four-sided polygon that has at least two right angles must be a rectangle or a square. De

nna wrote that a four-sided polygon needs at least three right angles to be a rectangle or a square. Who is right? Explain your answer.
Mathematics
2 answers:
Nonamiya [84]3 years ago
7 0

Answer:

Denna is correct. The sum of the angles in a quadrilateral is 360°, so if 3 of the angles are 90°, the fourth must also be 90°, creating a rectangle or a square. A quadrilateral can be drawn with the angles 90°, 90°, 120°, and 60°, but it is not a rectangle. Balavan is incorrect.

e2020 sample response

Step-by-step explanation:


gregori [183]3 years ago
4 0
A quadrilateral with only 2 right angles could be a trapezoid so Balavan is wrong.  Denna is right because if 3 angles are right angles the the  fourth angle must also be a right angle and has to be a square or rectangle.
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Answer:

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8(5y - 8) - (5y + 3)

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Which four inequalities can be used to find the solution to this absolute value inequality?
natita [175]

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the inequality:

3 ≤ |x + 2| ≤ 6

Hence:

x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)

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