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allsm [11]
3 years ago
9

Rate of diffusion depends upon:

Chemistry
1 answer:
Gelneren [198K]3 years ago
3 0

Answer:

The diffusion rate depends on several factors: the concentration gradient (the increase or decrease in concentration from one point to another); the amount of surface area available for diffusion; and the distance the gas particles must travel.

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3 years ago
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An unknown compound contains 38.7 % calcium, 19.9 % phosphorus and 41.2 % oxygen. what is the empirical formula of this compound
Temka [501]

The amount per 100 g is:

38.7 % calcium = 38.7g Ca / 100g compound = 38.7g

19.9 % phosphorus = 19.9g P / 100g compound = 19.9g

41.2 % oxygen = 41.2g O / 100g compound = 41.2g

The molar amounts of calcium, phosphorus and oxygen in 100g sample are calculated by dividing each element’s mass by its molar mass:

Ca = 38.7/40.078 = 0.96

P = 19.9/30.97 = 0.64

O = 41.2/15.99 = 2.57

C0efficients for the tentative empirical formula are derived by dividing each molar amount by the lesser value that is 0.64 and in this case, after that multiply wih 2.

Ca = 0.96 / 0.64 = 1.5=1.5 x 2 = 3

P = 0.64 / 0.64 = 1 = 1x2= 2

O = 2.57 / 0.64 = 4= 4x2= 8

Since, the resulting ratio is calcium 3, phosphorus 2 and oxygen 8

<span>So, the empirical formula of the compound is Ca</span>₃(PO₄)₂

5 0
3 years ago
If a buffer solution is 0.130 M in a weak acid (K_a = 1.7 x 10^-5) and 0.590 M in its conjugate base, what is the pH?
Serggg [28]
Use the Henderson-Hasselbach equation:
pH = pKa + log[base]/[acid]
pH = -log(1.7 x 10^-5) + log(0.590/0.130) = 5.43
8 0
3 years ago
Which statements describe elements?
monitta

Answer: B,C,D

Explanation: Who ever reads this have a great day and stay safe :}

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A sample of a mineral solid weighing 28.5 g was added to a graduated cylinder filled with to a level of 20.3 mL. As a result, th
bonufazy [111]

Answer:

2.8 g/mL is the density of the mineral.

Explanation:

The mass, m=28.5\ g

Volume of the object = Volume of water level rose - Initial volume of water = 30.5 mL - 20.3 mL = 10.2 mL

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

\rho=\frac{28.5\ g}{10.2 mL}=2.8\ g/mL

<u>2.8 g/mL is the density of the mineral.</u>

8 0
3 years ago
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