Question

Calculate the average Power in kilowatts required to pull a car up a ramp in the amount of work is 250 KJ over a period of 45 second

Answer 1

For this case we have that by definition, the average power is given by:

$P = \frac {W} {t}$

Where:

W: It is the work done

t: It's time

According to the data we have to:

$W = 250 \ KJ = 250,000 \ J\\t = 45 \ s$

So:

$P = \frac {250,000} {45}\\P = 5555.55 \ watts = 5.56 \ kw$

Answer:

$5.56 \ kw$