Over time, the substances will reach equilibrium, meaning the heat calories lost by Substance 1 will be gained by Substance 2. Therefore, Substance 2 will eventually gain 40 calories of heat.
Answer:
Resistivity, electrical resistance of a conductor of unit cross-sectional area and unit length.
Explanation:
A characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors.
Answer;
Q = 359.2-J
Explanation;
Given that;
Constants for mercury at 1 atm
Heat capacity of Hg(l) is 28.0 J/(mol*K)
melting point is 234.32 K
Enthalpy of fusion is 2.29 kJ/mol
17.7-g Hg / 200.6g/mol = 0.0882 mol Hg;
°C + 273 = 298 K;
2.29-kJ/mol = 2290-J/mol
Q = (m x ΔT x Cp) + (m x Hf)
Q = 0.0882-mol x (298 - 234.32) x 28.0-J/mol*K) + (0.0882-mol x 2290-J/mol)
Q = 157.26-J + 201.978-J
Q = 359.2-J
Q=359-J (3 sig fig allowed due to 17.7-g given in problem)
Answer:
V = 1280 [V]
Explanation:
To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the resistance by the current.
Therefore we have:
V = I*R
where:
V = voltage [V] (Units of volts)
I = current = 4 [amp]
R = resistance = 320 [ohms]
V = 4*320
V = 1280 [V]
