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ZanzabumX [31]
4 years ago
9

Calculate the average Power in kilowatts required to pull a car up a ramp in the amount of work is 250 KJ over a period of 45 se

cond
Physics
1 answer:
kherson [118]4 years ago
5 0

For this case we have that by definition, the average power is given by:

P = \frac {W} {t}

Where:

W: It is the work done

t: It's time

According to the data we have to:

W = 250 \ KJ = 250,000 \ J\\t = 45 \ s

So:

P = \frac {250,000} {45}\\P = 5555.55 \ watts = 5.56 \ kw

Answer:

5.56 \ kw

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Answer:

true stress = 992.8 MPA

true strain = 1.386

Explanation:

see the attached file

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3 years ago
The substances in the table are combined, and Substance 1 loses 40 calories of heat. How many calories of heat will Substance 2
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Over time, the substances will reach equilibrium, meaning the heat calories lost by Substance 1 will be gained by Substance 2. Therefore, Substance 2 will eventually gain 40 calories of heat.

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What is resistivity?​
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Answer:

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Calculate the heat energy released when 17.7 g of liquid mercury at 25.00 °c is converted to solid mercury at its melting point.
maria [59]

Answer;

Q = 359.2-J  

Explanation;

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Q = (m x ΔT x Cp) + (m x Hf)  

Q = 0.0882-mol x (298 - 234.32) x 28.0-J/mol*K) + (0.0882-mol x 2290-J/mol)  

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8 0
3 years ago
A motor with a resistance of 320 is connected to a voltage source. Four amps of current flows
cricket20 [7]

Answer:

V = 1280 [V]

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V = 4*320

V = 1280 [V]

3 0
3 years ago
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