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ZanzabumX [31]
4 years ago
9

Calculate the average Power in kilowatts required to pull a car up a ramp in the amount of work is 250 KJ over a period of 45 se

cond
Physics
1 answer:
kherson [118]4 years ago
5 0

For this case we have that by definition, the average power is given by:

P = \frac {W} {t}

Where:

W: It is the work done

t: It's time

According to the data we have to:

W = 250 \ KJ = 250,000 \ J\\t = 45 \ s

So:

P = \frac {250,000} {45}\\P = 5555.55 \ watts = 5.56 \ kw

Answer:

5.56 \ kw

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slega [8]

2.1 kg of sodium bicarbonate is equal to the 2.1 x 10¹² ng of sample. Option D is correct.

Mass is the quantity of the substance in the body or object. The SI unit of mass is Kilogram.

There are other units of measure,

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First convert kg to gram,

Since, 1 Kg = 1000 g

2.1 kg = grams of sample

So,

Do the cross multiplication,

\rm mass\ of\ sample = \dfrac {2.1\ kg \times  1000\ g }{ 1 kg}\\\\\rm mass\ of\ sample =2100 g

Now, convert 2100 g to nano-grams

Since, 1 g = 1 x 10⁹ ng

2100 g = ng of sample

So,

Do the cross multiplication,

\rm mass\ of\ sample  = \dfrac {2100 g \times  1 \times  10^9 ng }{1\ g}\\\\\rm mass\ of\ sample  = 2.1 \times 10^1^2 ng

Therefore, 2.1 kg of  sodium bicarbonate is equal to the 2.1 x 10¹² ng of sample.

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