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notka56 [123]
4 years ago
8

The junction rule describes the conservation of which quantity? Note that this rule applies only to circuits that are in a stead

y state.
Physics
2 answers:
denis-greek [22]4 years ago
5 0

Explanation:

The junction rule says that the sum of the currents going into a junction must equal the sum of the currents leaving a junction.  This describes the conservation of current.

Reptile [31]4 years ago
5 0

"Kirchhoff's Junction Rule" and "Kirchhoff's Current Law" are the same thing.

The rule is that the amount of current flowing IN to any point in a circuit is equal to the amount of current flowing OUT of the same point.  EVEN if the point is a complicated 'junction' with a thousand different paths in and out of it  !

This whole idea is pretty obvious if you understand the law of <em>Conservation of Electric Charge</em>.  Charge can't be created out of nothing, and it can't disappear or be destroyed.  So whenever you see charge appear, it had to come from somewhere; and whenever you see charge disappear, it had to go somewhere.

That's exactly what's happening at the 'junction' in an electric circuit.  Current into the junction brings charge into it.  The charge can't pile up there, and it can't just disappear, so it has to leave the junction in a current that's exactly the same size as the current that brought it there.

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4 years ago
A 110 n force and a 55 n force both act on an object point p. the 110 n force acts at 90 degrees. the 55 n force acts at 0 degre
ss7ja [257]
<span>To determine the magnitude and the direction of the resultant force, we assume that the forces are in XY coordinate plane and the angles that are given are from  the x axis.
 </span>
<span>The 110 N force is said to act at 90 deg which means it is along the Y axis. The </span><span>55 N force is said to act at 0 deg which means it is along the X axis. so, a right angle is made by the two forces. Thus, the
</span>
<span>X component of the resultant force = 55 N </span>
<span>Y component of the resultant force = 110 N </span>
<span>Magnitude of the resultant force would be calculated as follows:
R = √(Fx^2 + Fy^2)
R = √(55^2 + 110^2)  </span>
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<span>The resultant force  would have its terminal side in the x-axis. We calculate angle θ as follows:
 </span>
<span>tan θ = Fy/Fx </span>
<span>tan θ = 110 N /55 N = 2
</span>θ = arctan(2) 
θ <span>= 63.4 degrees
</span>Therefore, the m<span>agnitude of the resultant force is 123 N and the direction would be at an angle of 63.4 degrees.</span>
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