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stiks02 [169]
3 years ago
8

Point P is the midpoint of both MR and NQ, which are on the same line. If MN=26, NP=3x+4, and QR=6x+2, find NP.

Mathematics
1 answer:
sammy [17]3 years ago
7 0

Answer: NP= 16 cm

Explanation:

As we shown in the figure below :

Since P is the midpoint of MN and  NQ

So, We consider ΔMNP and ΔPQR,

∠MPN=∠QPR  (∵ Vertically opposite angles are equal)

MP=PR  (∵ P is the mid point of MR)

NP=PQ  (∵P is the midpoint of NQ)

So, ΔMNQ ≅ ΔPQR  (∵By SAS congruence )

∴ 26=6x+2 \text{(By CPCT )}\\26-2=6x\\24=6x\\\frac{24}{6}=x\\4=x

So, NP=3x+4=3\times 4+4=12+4=16 cm

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40 square inches.

Step-by-step explanation:

It is given that the new club sticker is in the shape of a triangle.

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Area of triangle =\dfrac{1}{2}\times 10\times 8

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3 years ago
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Step-by-step explanation:

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At a certain college the ratio of men to women is 6 to 5. If there are 3520 total students how many men are there.
notsponge [240]

Answer:

1920 men are there in college.

Step-by-step explanation:

Given the statement: At a certain college, the ratio of men to women is 6 to 5. If there are 3520 total students.

Ratio states that it is just a comparison between, or a relating of, two different things.

i.e a to b or a: b

Ratio of men to women:

Men : Women = 6: 5

Let x be the number.

Total number of Men in college = 6x and Total number of women = 5x

Since, total number of students = 3520

⇒6x + 5x = 3520

Combine like terms;

11x = 3520

Divide by 11 on both sides we get;

x = 320

Therefore, total number of men in college = 6x = 6(320) = 1920


4 0
2 years ago
Divid 15 into two parts such that the sum of their reciprocal is 3/10
Klio2033 [76]
From the information obtained from the question, two equations can be created:
 
Let x and z be the two numbers (parts)

\frac{1}{z}   +   \frac{1}{x}  =   \frac{3}{10} .  .  .  . (1)

z  +   x  =  15  .  .  .  . (2)

By transposing (2), make 'z' the subject of the equation
z = 15 - x  .  .  .  . (3)

By substituting (3) into equation (1) to find a value for x
\frac{1}{(15 - x)} + \frac{1}{x} = \frac{3}{10}

\frac{15}{( 15 - x ) ( x )}  =   \frac{3}{10}

3 ( - x^{2}  + 15 x )  =  150

3 x^{2}  - 45x + 150 = 0

⇒  ( x - 5 )  ( x - 10 )  = 0

∴ either ( x - 5) = 0        OR    ( x - 10 ) = 0

Thus x = 5 or x = 10

By substituting the values of x into (2) to find z

     z + (5) = 15       OR      z + (10) = 15

    ⇒      z = 10      OR                 z = 5

So, the two numbers or two parts into which fifteen is divided to yield the desired results are 5 and 10.





5 0
3 years ago
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