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Umnica [9.8K]
3 years ago
11

What is the net ionic equation for the reaction ofFeCl3 and KOH in water?

Chemistry
1 answer:
Levart [38]3 years ago
8 0

Answer:

Fe³⁺(aq) + 3 OH⁻(aq) → Fe(OH)₃(s)

Explanation:

First, we will write the molecular equation because it is the easiest to balance.

FeCl₃(aq) + 3 KOH(aq) → Fe(OH)₃(s) + 3 KCl(aq)

The full ionic equation includes all the ions and the molecular species.

Fe³⁺(aq) + 3 Cl⁻(aq) + 3 K⁺(aq) + 3 OH⁻(aq) → Fe(OH)₃(s) + 3 K⁺(aq) + 3 Cl⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and the molecular species.

Fe³⁺(aq) + 3 OH⁻(aq) → Fe(OH)₃(s)

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A solution is prepared by dissolving 27.7 g of cacl2 in 375 g of water. the density of the resulting solution is 1.05 g/ml. the
bagirrra123 [75]
The answer is 6.88.
Solution:
We can calculate for the percent composition of CaCl2 by mass by dividing the mass of the CaCl2 solute by the mass of the solution and then multiply by 100. The total mass of the resulting solution is the sum of the mass of CaCl2 solute and the mass of water solvent. Therefore, the percent composition of CaCl2 by mass is 
     % by mass = (mass of the solute / mass of the solution)*100 
                        = mass of solute / (mass of the solute + mass of the solvent)*100
                        = (27.7 g CaCl2 / 27.7g + 375g) * 100 
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3 years ago
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djverab [1.8K]
<span><u><em>Answer:</em></u>
All of the above

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How many grams of fluorine are needed to react with 8.5g of phosphorus?
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Step 1: write the equation:

                                          P₄(s) + 6F₂(g) → 4PF₃(g) 


Step 2: Molar mass of P₄ = 30.97 g/mol × 4 = 123.88 g/mol


Step 3: Number of moles of phosphorus

                                                    n = m/M 

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Step 4: 0.07 × 12 = 0.84 moles of fluorine.

Fluorine is diatomic gas so we multiplied the number of moles by 12.


Step 5: To find the mass of fluorine we multiply the number of moles with the molar mass.

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