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3 years ago

Complete the sentence. ______________ is thought to be most responsible for the salinity of the oceans.

1 answer:

5 0

The best and most correct answer among the choices provided by your question is the fourth choice or letter D. Natural run-off from mountain ranges is thought to be most responsible for the salinity of the oceans.

After years and years of river inflow and evaporation, the salt content of the lake water built up to the present levels. The same process made the seas salty. Rivers carry dissolved salts to the ocean. Water evaporates from the oceans to fall again as rain and to feed the rivers, but the salts remain in the ocean.

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How many grams of SO2 can be formed from 0.622 mole FeS2

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3 years ago

Zn + 2 HCl --> ZnCl2 + H2 How many moles of hydrochloric acid (HCl) are used (assume a complete reaction) if 8.3 moles of zin

uysha [10]

Answer:

E. 16.6 mol HCl

Explanation:

The equation for the reaction is;

Zn + 2 HCl --> ZnCl2 + H2

From the reaction 2 moles of HCl produces 1 mole of ZnCl2

Therefore; 8.3 moles of ZnCl2 will be produced by;

= 8.3 moles ×2

= 16.6 Moles of HCl

Therefore; E. 16.6 mol HCl

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4 years ago

Special structures in the cells of plants capture sunlight energy to power photosynthesis. What materials must plants obtain fro

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Answer:

Sunlight

Water

And carbon dioxide

Additional information :

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3 years ago

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jek_recluse [69]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

Given:

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

To determine:

The mean free path, λ

Calculation:

The mean free path is related to the collision cross section by the following equation:

$\lambda =\frac{1}{n\sigma }------(1)$

where n = number density

$n = \frac{P}{kT}-----(2)$

Substituting for P, k and T in equation (2) gives:

$n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\ m^{3}$

Next, substituting for n and σ in equation (1) gives:

$\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m$

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3 years ago