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dezoksy [38]
3 years ago
12

Complete the sentence. ______________ is thought to be most responsible for the salinity of the oceans.

Chemistry
1 answer:
Anettt [7]3 years ago
5 0
The best and most correct answer among the choices provided by your question is the fourth choice or letter D. Natural run-off from mountain ranges <span>is thought to be most responsible for the salinity of the oceans.

</span>After years and years of river inflow and evaporation, the salt<span> content of the lake water built up to the present levels. The same process made the seas </span>salty<span>. Rivers carry dissolved salts to the </span>ocean<span>. Water evaporates from the </span>oceans<span> to fall again as rain and to feed the rivers, but the salts remain in the </span>ocean<span>.</span>
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they will be different

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How many hydrogen atoms are in 3 molecules of ethyl alcohol, C2H3OH
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The idea that the behavior of the states of matter is determined by the kinetic energy and movement of their particles is called
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In an experiment, a 0.5297 g sample of diphenylacetylene (C14H10) is burned completely in a bomb calorimeter. The calorimeter is
V125BC [204]

Answer:

the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

Explanation:

Given that:

mass of diphenylacetylene (C_{14}H_{10}) = 0.5297 g

Molar Mass of diphenylacetylene (C_{14}H_{10}) = 178.21 g/mol

Then number of moles of diphenylacetylene (C_{14}H_{10})  = \frac{mass}{molar \ mass}

= \frac{0.5297  \ g }{178.24 \  g/mol}

= 0.002972 mol

By applying the law of calorimeter;

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = Heat absorbed by H_2O + Heat absorbed  by the calorimeter

Heat liberated  by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  =  msΔT + cΔT

= 1369 g  × 4.184 J g⁻¹°C⁻¹ × (26.05 - 22.95)°C + 916.9 J/°C (26.05 - 22.95)°C

= 17756.48 J + 2842.39 J

= 20598.87 J

Heat liberated by 0.002972 mole of diphenylacetylene (C_{14}H_{10})  = 20598.87 J

Heat liberated by 1 mole of  diphenylacetylene (C_{14}H_{10}) will be = \frac{20598.87 \ J}{0.002972 \ mol}

= 6930979.139 J/mol

= 6930.98 kJ/mol

Since heat is liberated ; Then, the Molar heat of  Combustion  of  diphenylacetylene (C_{14}H_{10})  = -6.931 *10^3 \ kJ/mol

3 0
3 years ago
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