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inna [77]
3 years ago
6

In which state of matter are water molecules measured as having a comparatively high temperature?

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

water vapor

because solid ice is a matter

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In the scientific process what is the purpose of the experiment
jasenka [17]
A to test the hypothesis
6 0
3 years ago
How many ml of 12.0 M H2S04 are needed to make 500.0 ml of a 1.00 M solution? What happens to the freezing point and the boiling
lora16 [44]

Answer:

41.66 mL of 12.0 M sulfuric acid are needed.

Explanation:

Concentration of sulfuric acid solution taken =M_1=12.0M

Volume of the 12.0 M Solution = V_1

Concentration of required solution = M_2=1.00M

Volume of required 1.00 M solution = V_2=500.0 mL

M_1V_1=M_2V_2 (Dilution)

V_1=\frac{1.00 M\times 500.0 mL}{12.0 M}=41.66 mL

41.66 mL of 12.0 M sulfuric acid are needed.

The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.

3 0
3 years ago
What volume (mL) of the sweetened tea described in Example 1 contains the same amount of sugar (mol) as 10 mL of the soft drink
S_A_V [24]

The question is incomplete, the complete question is:

What volume (mL) of the sweetened tea described in Example 3.14 contains the same amount of sugar (mol) as 10 mL of the soft drink in this example. The example is attached below.

<u>Answer:</u> 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

<u>Explanation:</u>

We first calculate the number of moles of soft drink in a volume of 10 mL

The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}} .....(1)

Taking the concentration of soft drink from the example be = 0.375 M

Volume of solution = 10 mL

Putting values in equation 1, we get:

0.375=\frac{\text{Moles of sugar in soft drink}\times 1000}{10}\\\\\text{Moles of sugar in soft drink}=\frac{0.375\times 10}{1000}=0.00375mol

<u>Calculating volume of sweetened tea:</u>

Moles of sugar = 0.00375 mol

Molarity of sweetened tea = 0.05 M

Putting values in equation 1, we get:

0.05=\frac{0.00375\times 1000}{\text{Volume of sweetened tea}}\\\\\text{Volume of sweetened tea}=\frac{0.00375\times 1000}{0.05}=75mL

Hence, 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

5 0
3 years ago
Just need 2 more, please help asap!!
Digiron [165]

Answer:

2. A resistor

3. Transistor

Sorry about before, go the answers now!

7 0
3 years ago
Q8.what happened to the mixture?
Natali [406]
Idkkkkkkkkkkkkkkkkkkk
3 0
3 years ago
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