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Rudik [331]
4 years ago
7

What do carbon 12 carbon 13 and carbon 14 have in common?

Chemistry
1 answer:
tiny-mole [99]4 years ago
7 0

Answer:

They have all the same number of protons and electrons ( 6)

Explanation:

Carbon 12, Carbon 13 and Carbon 14 are all isotopes of Carbon.

The definition of an isotope is: They have the same number of protons (and electrons), but a different number of neutrons. Different isotopes of the same element have different masses.

Carbon 12 means an isotope with mass 12 u

it has 6 protons,(and 6 electrons) and 6 neutrons : 6 neutrons + 6 protons = 12

Carbon 13 is an isotope with mass 13 u

It has the same amount  of protons  ( and electrons) as Carbon 12, so 6 protons and 6 electrons

13 - 6 = 7 ⇒ Carbon 13 has 7 neutrons

Carbon 14 is an isotope with mass 14

it has the same of protons ( and electrons) as Carbon 12 and Carbon 13, so 6 protons and 6 electrons

14 - 6 = 8 ⇒ Carbon 14 has 8 neutrons

We can conclude that Carbon 12, Carbon 13 and Carbon 14 are 3 isotopes of Carbon. They all have the same number of protons (and electrons) = 6.

This means the isotopes will also have the same atomic number, because they are all isotopes of the same element.

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A gas is at a pressure of 4.30 atm. what is this pressure in kilopascals? in mm hg?
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Units to measure pressure are as follows
atm - atmospheric pressure units
kPa - kilo Pascals
mm Hg - milimeters Hg
conversion units are;
 1 atm = 101 325 Pa
therefore 4.30 atm = 101 325 Pa / atm x 4.30 atm = 435.7 Pa

1 atm = 760.0 mm Hg
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answers are 435.7 Pa and 3268 mm Hg
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Answer:

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Explanation:

Step 1:

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Step 2:

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AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

The above equation can be balanced as follow:

There are 3 atoms of Mn on the left side of the equation and 1 atom on the right side. It can be balance by putting 3 in front of MnO4− as shown below:

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 12 atoms of O on the right side and a total of 3 atoms on the left side. It can be balance by putting 5 in front of AsO2− and 2 in front of H2O as shown below:

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There are 4 atoms of H on the left side and 1 atom on the right side. It can be balance by putting 4 in front of H+ as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + 4H+(aq)

There are 5 atoms of As on the left side and 1 atom on the right side. It can be balance by putting 5 in front of As as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → 5As(s) + 3MnO4−(aq) + 4H+(aq)

Now the equation is balanced

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